Option A: Enthalpy
Option B: Pressure
Option C: Entropy
Option D: None of these
Correct Answer: Entropy ✔
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Option A: Minimum number of degree of freedom of a system is zero
Option B: Degree of freedom of a system containing a gaseous mixture of helium, carbon dioxide and
Option C: For a two phase system in equilibrium made up of four non-reacting chemical species, the
Option D: Enthalpy and internal energy change is zero during phase change processes like melting,
Correct Answer: D. Enthalpy and internal energy change is zero during phase change processes like melting,
vaporisation and sublimation ✔
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Option A: Accomplishes only space heating in winter
Option B: Accomplishes only space cooling in summer
Option C: Accomplishes both A. and B
Option D: Works on Carnot cycle
Correct Answer: C. Accomplishes both A. and B ✔
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Option A: Single phase fluid of varying composition
Option B: Single phase fluid of constant composition
Option C: Open as well as closed systems
Option D: Both B. and C
Correct Answer: D. Both B. and C ✔
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Option A: Enthalpy
Option B: Entropy
Option C: Pressure
Option D: None of these
Correct Answer: Enthalpy ✔
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Option A: TR/(T2 – TR) × (T1 – T2)/T1
Option B: TR/(T2 – TR) × T1/(T1 – T2)
Option C: TR/(T1 – TR) × (T1 – T2)/T1
Option D: None of these
Correct Answer: A. TR/(T2 – TR) × (T1 – T2)/T1 ✔
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Option A: States that n1dμ1 + n2dμ2 + ….njdμj = 0, for a system of definite composition at constant
Option B: Applies only to binary systems
Option C: Finds no application in gas-liquid equilibria involved in distillation
Option D: None of these
Correct Answer: A. States that n1dμ1 + n2dμ2 + ….njdμj = 0, for a system of definite composition at constant
temperature and pressure ✔
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Option A: Molar concentration
Option B: Quantity (i.e. number of moles)
Option C: Both A. and B
Option D: Neither A. nor B
Correct Answer: C. Both A. and B ✔
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Option A: Zero
Option B: Positive
Option C: Negative
Option D: Indeterminate
Correct Answer: Zero ✔
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Option A: Specific volume
Option B: Temperature
Option C: Mass
Option D: Pressure
Correct Answer: Mass ✔
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Option A: Low temperature
Option B: High pressure
Option C: Both A. and B
Option D: Neither A. nor B
Correct Answer: C. Both A. and B ✔
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Option A: Extensive property
Option B: Intensive property
Option C: Force which drives the chemical system to equilibrium
Option D: Both B. and C
Correct Answer: D. Both B. and C ✔
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Option A: Path
Option B: Point
Option C: State
Option D: None of these
Correct Answer: Path ✔
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Option A: Carnot
Option B: Air
Option C: Absorption
Option D: vapour-ejection
Correct Answer: Absorption ✔
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Option A: Joule-Thomson co-efficient
Option B: Specific heat at constant pressure (Cp)
Option C: co-efficient of thermal expansion
Option D: Specific heat at constant volume (CV)
Correct Answer: co-efficient of thermal expansion ✔
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Option A: Increased COP
Option B: Same COP
Option C: Decreased COP
Option D: Increased or decreased COP; depending upon the type of refrigerant
Correct Answer: Increased COP ✔
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Option A: 0.25
Option B: 0.5
Option C: 0.75
Option D: 1
Correct Answer: 0.5 ✔
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Option A: 0.5
Option B: 3.5
Option C: 4.5
Option D: 8.5
Correct Answer: 3.5 ✔
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Option A: J/s
Option B: J.S
Option C: J/kmol
Option D: kmol/J
Correct Answer: J.S ✔
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Option A: 1.987 cal/gm mole °K
Option B: 1.987 BTU/lb. mole °R
Option C: Both A. and B
Option D: Neither A. nor B
Correct Answer: C. Both A. and B ✔
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Option A: Same in both the phases
Option B: Zero in both the phases
Option C: More in vapour phase
Option D: More in liquid phase
Correct Answer: Same in both the phases ✔
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Option A: SO2
Option B: NH3
Option C: CCl2F2
Option D: C2H4Cl2
Correct Answer: C2H4Cl2 ✔
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Option A: A homogeneous solution (say of phenol water) is formed
Option B: Mutual solubility of the two liquids shows a decreasing trend
Option C: Two liquids are completely separated into two layers
Option D: None of these
Correct Answer: A homogeneous solution (say of phenol water) is formed ✔
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Option A: (∂T/∂V)S, ni = -(∂P/∂S)V, ni
Option B: (∂S/∂P)T, ni = (∂V/∂T)P, ni
Option C: (∂S/∂V)T, ni = (∂P/∂T)V, ni
Option D: (∂T/∂P)S, ni = (∂V/∂S)P, ni
Correct Answer: (∂T/∂P)S, ni = (∂V/∂S)P, ni ✔
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Option A: Temperature
Option B: Pressure
Option C: Volume
Option D: None of these
Correct Answer: Pressure ✔
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Option A: Bertholet equation
Option B: Clausius-Clapeyron equation
Option C: Beattie-Bridgeman equation
Option D: None of these
Correct Answer: Clausius-Clapeyron equation ✔
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The melting point of paraffin wax (which contracts on solidification) __________ with pressure rise?
Option A: Increases
Option B: Decreases
Option C: Remains unchanged
Option D: Decreases linearly
Correct Answer: Increases ✔
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Option A: Cp < Cv
Option B: Cp = Cv
Option C: Cp > Cv
Option D: C ≥ Cv
Correct Answer: Cp = Cv ✔
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Option A: Isothermal
Option B: Adiabatic
Option C: Isobaric
Option D: Isometric
Correct Answer: Isothermal ✔
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Option A: Melting point of ice
Option B: Melting point of wax
Option C: Boiling point of liquids
Option D: None of these
Correct Answer: Melting point of ice ✔
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Option A: Less than
Option B: Same as
Option C: More than
Option D: Half
Correct Answer: Less than ✔
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Option A: Vapor pressure
Option B: Specific Gibbs free energy
Option C: Specific entropy
Option D: All (A), B. and (C)
Correct Answer: Vapor pressure ✔
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Option A: 0.15
Option B: 1.5
Option C: 4.5
Option D: 6.5
Correct Answer: 0.15 ✔
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Option A: (∂P/∂V)T
Option B: (∂V/∂T)P
Option C: (∂P/∂V)V
Option D: All (A), B. & (C)
Correct Answer: (∂P/∂V)T ✔
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Option A: Saturated vapour
Option B: Solid
Option C: Gas
Option D: Liquid
Correct Answer: Gas ✔
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Option A: Vapour pressure is relatively low and the temperature does not vary over wide limits
Option B: Vapour obeys the ideal gas law and the latent heat of vaporisation is constant
Option C: Volume in the liquid state is negligible compared with that in the vapour state
Option D: All A, B. and C
Correct Answer: D. All A, B. and C ✔
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Option A: Adiabatic
Option B: Reversible
Option C: Isothermal
Option D: None of these
Correct Answer: Isothermal ✔
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Option A: dE = Tds – PdV
Option B: dQ = CvdT + PdV
Option C: dQ = CpdT + Vdp
Option D: Tds = dE – PdV
Correct Answer: A. dE = Tds – PdV ✔
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Option A: Pressure
Option B: Volume
Option C: Temperature
Option D: All A, B. & C
Correct Answer: Temperature ✔
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Option A: A heating effect
Option B: No change in temperature
Option C: A cooling effect
Option D: Either A. or (C)
Correct Answer: A heating effect ✔
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Option A: Increases
Option B: Decreases
Option C: Remains unchanged
Option D: May increase or decrease; depends on the substance
Correct Answer: Increases ✔
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Option A: CV
Option B: Entropy change
Option C: Gibbs free energy
Option D: None of these
Correct Answer: None of these ✔
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Option A: R loge 4
Option B: R log10 4
Option C: Cv log10 4
Option D: Cv loge 4
Correct Answer: R loge 4 ✔
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Option A: Molar concentration
Option B: Temperature
Option C: Internal energy
Option D: None of these
Correct Answer: None of these ✔
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Option A: Sub-cooled
Option B: Saturated
Option C: Non-solidifiable
Option D: None of these
Correct Answer: Sub-cooled ✔
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Option A: Mass
Option B: Energy
Option C: Momentum
Option D: None of these
Correct Answer: Energy ✔
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Option A: Entropy
Option B: Temperature
Option C: Enthalpy
Option D: Pressure
Correct Answer: Pressure ✔
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Option A: Isothermal
Option B: Adiabatic
Option C: Isobaric
Option D: Isochoric
Correct Answer: Isothermal ✔
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Option A: Work required to refrigeration obtained
Option B: Refrigeration obtained to the work required
Option C: Lower to higher temperature
Option D: Higher to lower temperature
Correct Answer: Refrigeration obtained to the work required ✔
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Option A: At constant pressure
Option B: By throttling
Option C: By expansion in an engine
Option D: None of these
Correct Answer: By expansion in an engine ✔
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Option A: Same
Option B: Doubled
Option C: Halved
Option D: One fourth of its original value
Correct Answer: Same ✔
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Option A: More than
Option B: Less than
Option C: Equal to
Option D: Data insufficient, can’t be predicted
Correct Answer: Equal to ✔
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Option A: Pressure
Option B: Volume
Option C: Temperature
Option D: All A , B. and C
Correct Answer: Volume ✔
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Option A: Solid-vapor
Option B: Solid-liquid
Option C: Liquid-vapor
Option D: All A, B. and C
Correct Answer: D. All A, B. and C ✔
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Option A: Gibbs-Duhem
Option B: Gibbs-Helmholtz
Option C: Maxwell’s
Option D: None of these
Correct Answer: C. Maxwell’s ✔
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Option A: The amount of work needed is path dependent
Option B: Work alone cannot bring out such a change of state
Option C: The amount of work needed is independent of path
Option D: More information is needed to conclude anything about the path dependence or otherwise of
Correct Answer: The amount of work needed is path dependent ✔
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Option A: Increase the partial pressure of H2
Option B: Increase the partial pressure of I2
Option C: Increase the total pressure and hence shift the equilibrium towards the right
Option D: Not affect the equilibrium conditions
Correct Answer: Not affect the equilibrium conditions ✔
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Option A: -1.87
Option B: 0
Option C: 1.26
Option D: 3.91
Correct Answer: 0 ✔
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Option A: Hour
Option B: Day
Option C: Minute
Option D: Second
Correct Answer: Day ✔
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Option A: Sublimation
Option B: Vaporisation
Option C: Melting
Option D: Either A, B. or C.
Correct Answer: D. Either A, B. or C. ✔
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Option A: Work done under adiabatic condition
Option B: Co-efficient of thermal expansion
Option C: Compressibility
Option D: None of these
Correct Answer: Work done under adiabatic condition ✔
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Option A: Reverse Carnot cycle
Option B: Ordinary vapour-compression cycle
Option C: Vapour-compression process with a reversible expansion engine
Option D: Air refrigeration cycle
Correct Answer: Air refrigeration cycle ✔
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Option A: Chemical potential
Option B: Activity
Option C: Fugacity
Option D: Activity co-efficient
Correct Answer: Chemical potential ✔
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Option A: Snow melts into water
Option B: A gas expands spontaneously from high pressure to low pressure
Option C: Water is converted into ice
Option D: Both B. & C
Correct Answer: D. Both B. & C ✔
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Option A: Low pressure and high temperature
Option B: Low pressure and low temperature
Option C: Low temperature and high pressure
Option D: High temperature and high pressure
Correct Answer: Low temperature and high pressure ✔
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Option A: (∂T/∂V)S = – (∂P/∂S)V
Option B: (∂S/∂P)T = – (∂V/∂T)P
Option C: (∂V/∂S)P = (∂T/∂P)S
Option D: (∂S/∂V)T = (∂P/∂T)V
Correct Answer: (∂S/∂V)T = (∂P/∂T)V ✔
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Option A: Negative
Option B: Zero
Option C: Infinity
Option D: None of these
Correct Answer: Zero ✔
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Option A: The same
Option B: Less than
Option C: Greater than
Option D: Different than
Correct Answer: The same ✔
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Option A: RT d ln P
Option B: R d ln P
Option C: R d ln f
Option D: None of these
Correct Answer: RT d ln P ✔
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Option A: Ideal compression of air
Option B: Free expansion of an ideal gas
Option C: Adiabatic expansion of steam in a turbine
Option D: Adiabatic compression of a perfect gas
Correct Answer: Free expansion of an ideal gas ✔
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Option A: Increase
Option B: Decrease
Option C: Remain unaltered
Option D: Increase or decrease; depends on the particular reaction
Correct Answer: Remain unaltered ✔
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Option A: Decreases
Option B: Increases
Option C: Remain same
Option D: May increase or decrease; depends on the nature of the gas
Correct Answer: Decreases ✔
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Option A: T2/(T1 – T2)
Option B: T1/(T1 – T2)
Option C: (T1 – T2)/T1
Option D: (T1 – T2)/T2
Correct Answer: A. T2/(T1 – T2) ✔
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Option A: Property of the system
Option B: Path function
Option C: Point function
Option D: State description of a system
Correct Answer: Path function ✔
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For a constant pressure reversible process, the enthalpy change (ΔH) of the system is__________?
Option A: Cv.dT
Option B: Cp.dT
Option C: ∫ Cp.dT
Option D: ∫ Cv.dT
Correct Answer: Cp.dT ✔
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Option A: Equilibrium cannot be established
Option B: More ice will be formed
Option C: More water will be formed
Option D: Evaporation of water will take place
Correct Answer: More water will be formed ✔
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Option A: Tds = dE – dW = 0
Option B: dE – dW – Tds = 0
Option C: Tds – dE + dW < 0
Option D: Tds – dT + dW < 0
Correct Answer: C. Tds – dE + dW < 0 ✔
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Option A: T1/(T1-T2)
Option B: T2/(T1-T2)
Option C: T1/T2
Option D: T2/R1
Correct Answer: T1/(T1-T2) ✔
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Option A: 12 P1V1
Option B: 6 P1 V1
Option C: 3 P1V1
Option D: P1 V1
Correct Answer: 3 P1V1 ✔
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Option A: Temperature
Option B: Specific heat
Option C: Volume
Option D: Pressure
Correct Answer: Temperature ✔
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Option A: If an insoluble gas is passed through a volatile liquid placed in a perfectly insulated container,
Option B: A process is irreversible as long as Δ S for the system is greater than zero
Option C: The mechanical work done by a system is always equal to∫P.dV
Option D: The heat of formation of a compound is defined as the heat of reaction leading to the
Correct Answer: D. The heat of formation of a compound is defined as the heat of reaction leading to the
formation of the compound from its reactants ✔
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Option A: Zeroth
Option B: First
Option C: Second
Option D: Third
Correct Answer: Second ✔
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Option A: Increase
Option B: Decrease
Option C: Remain same
Option D: Increase in summer and will decrease in winter
Correct Answer: Increase ✔
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Option A: Adiabatic expansion
Option B: Joule-Thomson effect
Option C: Both A. and B
Option D: Neither A. nor B
Correct Answer: C. Both A. and B ✔
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Option A: Decreases
Option B: Increases
Option C: Remains constant
Option D: Decreases logarithmically
Correct Answer: Increases ✔
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Entropy change of the reaction, H2O (liquid) → H2O (gas), is termed as the enthalpy of__________?
Option A: Solution
Option B: Vaporisation
Option C: Formation
Option D: Sublimation
Correct Answer: Vaporisation ✔
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Option A: Less pronounced
Option B: More pronounced
Option C: Equal
Option D: Data insufficient, can’t be predicted
Correct Answer: More pronounced ✔
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Option A: Heating takes place
Option B: Cooling takes place
Option C: Pressure is constant
Option D: Temperature is constant
Correct Answer: Cooling takes place ✔
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Option A: Straight line
Option B: Sine curve
Option C: Parabola
Option D: Hyperbola
Correct Answer: Straight line ✔
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Option A: Tds = dE + dW
Option B: dE – dW = Tds
Option C: dW – dE = Tds
Option D: Tds – dW + dE >0
Correct Answer: Tds = dE + dW ✔
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