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Thermodynamics For Chemical MCQs

Option A: Specific heat at constant pressure (Cp)

Option B: Specific heat at constant volume (Cv)

Option C: Joule-Thompson co-efficient

Option D: None of these

Correct Answer: Joule-Thompson co-efficient


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Option A: Water

Option B: Ammonia

Option C: Freon

Option D: Brine

Correct Answer: Water


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Option A: Conduction

Option B: Convection

Option C: Radiation

Option D: Condensation

Correct Answer: Condensation


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Option A: Doubling the absolute temperature as well as pressure of the gas

Option B: Reducing pressure to one fourth at constant temperature

Option C: Reducing temperature to one fourth at constant pressure

Option D: Reducing the temperature to half and doubling the pressure

Correct Answer: Reducing pressure to one fourth at constant temperature


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Option A: Pressure and temperature

Option B: Reduced pressure and reduced temperature

Option C: Critical pressure and critical temperature

Option D: None of these

Correct Answer: Reduced pressure and reduced temperature


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Option A: Δ H = 0 and ΔS = 0

Option B: Δ H ≠ 0 and ΔS = 0

Option C: Δ H ≠ 0 and ΔS ≠ 0

Option D: Δ H = 0 and ΔS ≠ 0

Correct Answer: Δ H ≠ 0 and ΔS = 0


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Option A: Superheated

Option B: Desuperheated

Option C: Non-condensable

Option D: None of these

Correct Answer: Superheated


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Option A: Momentum

Option B: Mass

Option C: Energy

Option D: None of these

Correct Answer: Energy


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Option A: Heat capacity of a crystalline solid is zero at absolute zero temperature

Option B: Heat transfer from low temperature to high temperature source is not possible without external

Option C: Gases having same reduced properties behaves similarly

Option D: None of these

Correct Answer: Heat capacity of a crystalline solid is zero at absolute zero temperature


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Option A: (∂T/∂V)S = (∂p/∂S)V

Option B: (∂T/∂P)S = (∂V/∂S)P

Option C: (∂P/∂T)V = (∂S/∂V)T

Option D: (∂V/∂T)P = -(∂S/∂P)T

Correct Answer: (∂V/∂T)P = -(∂S/∂P)T


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Option A: Enhanced COP

Option B: Decreased COP

Option C: No change in the value of COP

Option D: Increased or decreased COP; depending upon the type of refrigerant

Correct Answer: Enhanced COP


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Option A: Third law of thermodynamics

Option B: Second law of thermodynamics

Option C: Nernst heat theorem

Option D: Maxwell’s relations

Correct Answer: Third law of thermodynamics


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Option A: (∂P/∂V)S = (∂P/∂V)T

Option B: (∂P/∂V)S = [(∂P/∂V)T]Y

Option C: (∂P/∂V)S = y(∂P/∂V)T

Option D: (∂P/∂V)S = 1/y(∂P/∂V)T

Correct Answer: (∂P/∂V)S = y(∂P/∂V)T


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Option A: -94 kcal

Option B: > -94 kcal

Option C: < – 94 kcal

Option D: Zero

Correct Answer: Zero


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Option A: Violates second law of thermodynamics

Option B: Involves transfer of heat from low temperature to high temperature

Option C: Both A. and B

Option D: Neither A. nor B

Correct Answer: Involves transfer of heat from low temperature to high temperature


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Option A: 1st

Option B: Zeroth

Option C: 3rd

Option D: None of these

Correct Answer: Zeroth


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Option A: Isobaric

Option B: Isothermal

Option C: Adiabatic

Option D: None of these

Correct Answer: Isothermal


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A. Δ S1 is always Δ SR
C. Δ S1 is always > Δ SR
D. Δ S1 is always = Δ SR

Correct Answer: Δ S1 is always > Δ SR


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Option A: Van Laar equation

Option B: Margules equation

Option C: Wilson’s equation

Option D: All A, B. and C

Correct Answer: D. All A, B. and C


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Option A: Adiabatic

Option B: Isothermal

Option C: Isometric

Option D: None of these

Correct Answer: Isothermal


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Option A: +ve

Option B: -ve

Option C: 0

Option D: Either of the above three; depends on the nature of refrigerant

Correct Answer: 0


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Option A: A = H – TS

Option B: A = E – TS

Option C: A = H + TS

Option D: None of these

Correct Answer: B. A = E – TS


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Option A: Fugacity

Option B: Activity co-efficient

Option C: Free energy

Option D: None of these

Correct Answer: None of these


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Option A: Isothermal

Option B: Adiabatic

Option C: Isentropic

Option D: None of these

Correct Answer: Isothermal


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Option A: Heating occurs

Option B: Cooling occurs

Option C: Pressure is constant

Option D: Temperature is constant

Correct Answer: Heating occurs


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Option A: No

Option B: Any real

Option C: Only ideal

Option D: Both B. and C.

Correct Answer: Only ideal


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Option A: More stable

Option B: Less stable

Option C: Not at all stable (like nascent O2)

Option D: Either more or less stable; depends on the compound

Correct Answer: More stable


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Option A: Pressure

Option B: Temperature

Option C: Both A. & B.

Option D: Neither A. nor B.

Correct Answer: Temperature


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Option A: Sublimation

Option B: Fusion

Option C: Transition

Option D: Vaporisation

Correct Answer: Transition


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Option A: 0

Option B:

Option C: +ve

Option D: -ve

Correct Answer: 0


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Option A: Volume of the liquid phase is negligible compared to that of vapour phase

Option B: Vapour phase behaves as an ideal gas

Option C: Heat of vaporisation is independent of temperature

Option D: All A , B. & C.

Correct Answer: D. All A , B. & C.


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Option A: Directly proportional

Option B: Inversely proportional

Option C: Equal

Option D: None of these

Correct Answer: Directly proportional


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Option A: By throttling

Option B: By expansion in an engine

Option C: At constant pressure

Option D: None of these

Correct Answer: By throttling


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Option A: Isothermal

Option B: Adiabatic

Option C: Isentropic

Option D: Polytropic

Correct Answer: Isentropic


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Option A: 0°C

Option B: 273°C

Option C: 100°C

Option D: -273°C

Correct Answer: 273°C


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Option A: Minimum

Option B: Zero

Option C: Maximum

Option D: None of these

Correct Answer: Maximum


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Option A: Escaping tendencies of the same substance in different phases of a system

Option B: Relative volatility of a mixture of two miscible liquids

Option C: Behaviour of ideal gases

Option D: None of these

Correct Answer: Escaping tendencies of the same substance in different phases of a system


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Option A: Temperature

Option B: Pressure

Option C: Volume

Option D: Entropy

Correct Answer: Pressure


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Option A: Closed

Option B: Open

Option C: Isolated

Option D: Non-thermodynamic

Correct Answer: Open


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Option A: Decreases

Option B: Increases

Option C: Remain same

Option D: Decreases linearly

Correct Answer: Increases


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Option A: Pressure vs. enthalpy

Option B: Pressure vs. volume

Option C: Enthalpy vs. entropy

Option D: Temperature vs. entropy

Correct Answer: Enthalpy vs. entropy


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Option A: +ve

Option B: 0

Option C: -ve

Option D:

Correct Answer: +ve


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Option A: Logarithmic

Option B: Arithmetic

Option C: Geometric

Option D: Harmonic

Correct Answer: Geometric


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Option A: Zero

Option B: Unity

Option C: Infinity

Option D: An indeterminate value

Correct Answer: Unity


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Option A: Process must be isobaric

Option B: Temperature must decrease

Option C: Process must be adiabatic

Option D: Both B. and C.

Correct Answer: D. Both B. and C.


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Option A: Heat

Option B: Momentum

Option C: Energy

Option D: Work

Correct Answer: Energy


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Option A: Direction of energy transfer

Option B: Reversible processes only

Option C: Irreversible processes only

Option D: None of these

Correct Answer: Direction of energy transfer


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Option A: Less

Option B: More

Option C: Same

Option D: Dependent on climatic conditions

Correct Answer: Less


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Option A: Is zero

Option B: Increases

Option C: Decreases whereas the entropy increases

Option D: And entropy both decrease

Correct Answer: Decreases whereas the entropy increases


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Option A: Chemical potential

Option B: Fugacity

Option C: Both A. and B

Option D: Neither A. nor B

Correct Answer: C. Both A. and B


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Option A: Temperature

Option B: Pressure

Option C: Composition

Option D: All (A), B. and (C)

Correct Answer: D. All (A), B. and (C)


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Option A: Isometric

Option B: Polytropic

Option C: Isentropic

Option D: Isobaric

Correct Answer: Polytropic


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Option A: Contracts

Option B: Expands

Option C: Has same volume

Option D: May contract or expand

Correct Answer: Contracts


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Option A: Less

Option B: More

Option C: Same

Option D: More or less depending upon the extent of work done

Correct Answer: More


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Option A: Isothermal

Option B: Adiabatic

Option C: Both A. & B

Option D: Neither A. nor B

Correct Answer: C. Both A. & B


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Option A: Virial co-efficients are universal constants

Option B: Virial co-efficients ‘B’ represents three body interactions

Option C: Virial co-efficients are function of temperature only

Option D: For some gases, Virial equations and ideal gas equations are the same

Correct Answer: Virial co-efficients are function of temperature only


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Option A: 0

Option B: 1

Option C: y = 1.44

Option D: 1.66

Correct Answer: 0


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Option A: Air cycle

Option B: Carnot cycle

Option C: Ordinary vapor compression cycle

Option D: Vapor compression with a reversible expansion engine

Correct Answer: Carnot cycle


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Option A: Oxygen

Option B: Nitrogen

Option C: Air

Option D: Hydrogen

Correct Answer: Hydrogen


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Option A: Latent heat of vaporisation

Option B: Chemical potential

Option C: Molal boiling point

Option D: Heat capacity

Correct Answer: Chemical potential


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Option A: μ = (∂P/∂T)H

Option B: μ = (∂T/∂P)H

Option C: μ = (∂E/∂T)H

Option D: μ = (∂E/∂P)H

Correct Answer: μ = (∂T/∂P)H


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Option A: 0

Option B:

Option C: +ve

Option D: -ve

Correct Answer: +ve


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Option A: Enthalpy remains constant

Option B: Entropy remains constant

Option C: Temperature remains constant

Option D: None of these

Correct Answer: Enthalpy remains constant


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Option A: Kp2/Kp1 = – (ΔH/R) (1/T2 – 1/T1)

Option B: Kp2/Kp1 = (ΔH/R) (1/T2 – 1/T1)

Option C: Kp2/Kp1 = ΔH (1/T2 – 1/T1)

Option D: Kp2/Kp1 = – (1/R) (1/T2 – 1/T1)

Correct Answer: A. Kp2/Kp1 = – (ΔH/R) (1/T2 – 1/T1)


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Option A: Water

Option B: Air

Option C: Evaporative

Option D: Gas

Correct Answer: Air


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Option A: Van Laar

Option B: Margules

Option C: Gibbs-Duhem

Option D: Gibbs-Duhem-Margules

Correct Answer: Margules


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Option A: +ve

Option B: 0

Option C: -ve

Option D:

Correct Answer: +ve


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Option A: Zero

Option B: Positive

Option C: Negative

Option D: None of these

Correct Answer: Negative


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Option A: -273

Option B: 0

Option C: -78

Option D: 5

Correct Answer: -78


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Option A: Freon-12

Option B: Ethylene

Option C: Ammonia

Option D: Carbon dioxide

Correct Answer: Ethylene


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Option A: Zero

Option B: Negative

Option C: Very large compared to that for endothermic reaction

Option D: Not possible to predict

Correct Answer: Not possible to predict


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Option A: 2.73

Option B: 28.3

Option C: 273

Option D: 283

Correct Answer: 28.3


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Option A: The energy change of a system undergoing any reversible process is zero

Option B: It is not possible to transfer heat from a lower temperature to a higher temperature

Option C: The total energy of system and surrounding remains the same

Option D: None of the above

Correct Answer: None of the above


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Option A: Isothermal

Option B: Isobaric

Option C: Polytropic

Option D: Adiabatic

Correct Answer: Isothermal


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Option A: Zero

Option B: Negative

Option C: More than zero

Option D: Indeterminate

Correct Answer: Zero


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Option A: ds = 0

Option B: ds <0

Option C: ds > 0

Option D: ds = Constant

Correct Answer: ds > 0


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Option A: Only enthalpy change (ΔH) is negative

Option B: Only internal energy change (ΔE) is negative

Option C: Both ΔH and ΔE are negative

Option D: Enthalpy change is zero

Correct Answer: Both ΔH and ΔE are negative


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Option A: Entropy

Option B: Temperature

Option C: Internal energy

Option D: Enthalpy

Correct Answer: Enthalpy


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Option A: (p + a/V2)(V – b) = nRT

Option B: PV = nRT

Option C: PV = A + B/V + C/V2 + D/V3 + …

Option D: None of these

Correct Answer: C. PV = A + B/V + C/V2 + D/V3 + …


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Option A: Entropy

Option B: Internal energy

Option C: Enthalpy

Option D: Gibbs free energy

Correct Answer: Gibbs free energy


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Option A: Eutectic

Option B: Triple

Option C: Plait

Option D: Critical

Correct Answer: Triple


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Option A: x

Option B: x + 1

Option C: x + 2

Option D: x + 3

Correct Answer: x


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Option A: Two temperatures only

Option B: Pressure of working fluid

Option C: Mass of the working fluid

Option D: Mass and pressure both of the working fluid

Correct Answer: Two temperatures only


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Option A: Non-uniformly

Option B: Adiabatically

Option C: Isobarically

Option D: Isothermally

Correct Answer: Isobarically


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Option A: Minimum temperature attainable

Option B: Temperature of the heat reservoir to which a Carnot engine rejects all the heat that is taken in

Option C: Temperature of the heat reservoir to which a Carnot engine rejects no heat

Option D: None of these

Correct Answer: Temperature of the heat reservoir to which a Carnot engine rejects no heat


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Option A: Adiabatic process

Option B: Endothermic reaction

Option C: Exothermic reaction

Option D: Process involving a chemical reaction

Correct Answer: Endothermic reaction


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Option A: 0°C and 760 mm Hg

Option B: 15°C and 760 mm Hg

Option C: 20°C and 760 mm Hg

Option D: 0°C and 1 kgf/cm2

Correct Answer: 0°C and 760 mm Hg


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Option A: √(2KT/m)

Option B: √(3KT/m)

Option C: √(6KT/m)

Option D: 3KT/m

Correct Answer: √(3KT/m)


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Option A: System and surroundings pressure be equal

Option B: Friction in the system should be absent

Option C: System and surroundings temperature be equal

Option D: None of these

Correct Answer: Friction in the system should be absent


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Option A: Increases with increase in pressure

Option B: Decreases with increase in temperature

Option C: Is independent of temperature

Option D: None of these

Correct Answer: None of these


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Option A: Critical temperature

Option B: Melting point

Option C: Freezing point

Option D: Both B. and C

Correct Answer: D. Both B. and C


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Option A: Only ΔE = 0

Option B: Only ΔH =0

Option C: ΔE = ΔH = 0

Option D: dQ = dE

Correct Answer: ΔE = ΔH = 0


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Option A: 0

Option B: 1

Option C: 2

Option D: 3

Correct Answer: 1


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Option A: Is the most efficient of all refrigeration cycles

Option B: Has very low efficiency

Option C: Requires relatively large quantities of air to achieve a significant amount of refrigeration

Option D: Both B. and C

Correct Answer: D. Both B. and C


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Option A: Free energy

Option B: Entropy

Option C: Refractive index

Option D: None of these

Correct Answer: Refractive index


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Option A: Ethyl chloride or methyl chloride

Option B: Freon-12

Option C: Propane

Option D: NH3 or CO2

Correct Answer: Ethyl chloride or methyl chloride


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Option A: Infinity

Option B: Unity

Option C: Constant

Option D: Negative

Correct Answer: Constant


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Option A: A gas may have more than one inversion temperatures

Option B: The inversion temperature is different for different gases

Option C: The inversion temperature is same for all gases

Option D: The inversion temperature is the temperature at which Joule-Thomson co-efficient is infinity

Correct Answer: The inversion temperature is different for different gases


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Option A: 5.2

Option B: 6.2

Option C: 0.168

Option D: Data insufficient, can’t be found out

Correct Answer: 5.2


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Option A: Reaction mechanism

Option B: Calculation of rates

Option C: Energy transformation from one form to another

Option D: None of these

Correct Answer: Energy transformation from one form to another


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