Option A: Specific heat at constant pressure (Cp)
Option B: Specific heat at constant volume (Cv)
Option C: Joule-Thompson co-efficient
Option D: None of these
Correct Answer: Joule-Thompson co-efficient ✔
Click for More Details
Option A: Water
Option B: Ammonia
Option C: Freon
Option D: Brine
Correct Answer: Water ✔
Click for More Details
Option A: Conduction
Option B: Convection
Option C: Radiation
Option D: Condensation
Correct Answer: Condensation ✔
Click for More Details
Option A: Doubling the absolute temperature as well as pressure of the gas
Option B: Reducing pressure to one fourth at constant temperature
Option C: Reducing temperature to one fourth at constant pressure
Option D: Reducing the temperature to half and doubling the pressure
Correct Answer: Reducing pressure to one fourth at constant temperature ✔
Click for More Details
Option A: Pressure and temperature
Option B: Reduced pressure and reduced temperature
Option C: Critical pressure and critical temperature
Option D: None of these
Correct Answer: Reduced pressure and reduced temperature ✔
Click for More Details
Option A: Δ H = 0 and ΔS = 0
Option B: Δ H ≠ 0 and ΔS = 0
Option C: Δ H ≠ 0 and ΔS ≠ 0
Option D: Δ H = 0 and ΔS ≠ 0
Correct Answer: Δ H ≠ 0 and ΔS = 0 ✔
Click for More Details
Option A: Superheated
Option B: Desuperheated
Option C: Non-condensable
Option D: None of these
Correct Answer: Superheated ✔
Click for More Details
Option A: Momentum
Option B: Mass
Option C: Energy
Option D: None of these
Correct Answer: Energy ✔
Click for More Details
Option A: Heat capacity of a crystalline solid is zero at absolute zero temperature
Option B: Heat transfer from low temperature to high temperature source is not possible without external
Option C: Gases having same reduced properties behaves similarly
Option D: None of these
Correct Answer: Heat capacity of a crystalline solid is zero at absolute zero temperature ✔
Click for More Details
Option A: (∂T/∂V)S = (∂p/∂S)V
Option B: (∂T/∂P)S = (∂V/∂S)P
Option C: (∂P/∂T)V = (∂S/∂V)T
Option D: (∂V/∂T)P = -(∂S/∂P)T
Correct Answer: (∂V/∂T)P = -(∂S/∂P)T ✔
Click for More Details
Option A: Enhanced COP
Option B: Decreased COP
Option C: No change in the value of COP
Option D: Increased or decreased COP; depending upon the type of refrigerant
Correct Answer: Enhanced COP ✔
Click for More Details
Option A: Third law of thermodynamics
Option B: Second law of thermodynamics
Option C: Nernst heat theorem
Option D: Maxwell’s relations
Correct Answer: Third law of thermodynamics ✔
Click for More Details
Option A: (∂P/∂V)S = (∂P/∂V)T
Option B: (∂P/∂V)S = [(∂P/∂V)T]Y
Option C: (∂P/∂V)S = y(∂P/∂V)T
Option D: (∂P/∂V)S = 1/y(∂P/∂V)T
Correct Answer: (∂P/∂V)S = y(∂P/∂V)T ✔
Click for More Details
Option A: -94 kcal
Option B: > -94 kcal
Option C: < – 94 kcal
Option D: Zero
Correct Answer: Zero ✔
Click for More Details
Option A: Violates second law of thermodynamics
Option B: Involves transfer of heat from low temperature to high temperature
Option C: Both A. and B
Option D: Neither A. nor B
Correct Answer: Involves transfer of heat from low temperature to high temperature ✔
Click for More Details
Option A: 1st
Option B: Zeroth
Option C: 3rd
Option D: None of these
Correct Answer: Zeroth ✔
Click for More Details
Option A: Isobaric
Option B: Isothermal
Option C: Adiabatic
Option D: None of these
Correct Answer: Isothermal ✔
Click for More Details
A. Δ S1 is always Δ SR
C. Δ S1 is always > Δ SR
D. Δ S1 is always = Δ SR
Correct Answer: Δ S1 is always > Δ SR ✔
Click for More Details
Option A: Van Laar equation
Option B: Margules equation
Option C: Wilson’s equation
Option D: All A, B. and C
Correct Answer: D. All A, B. and C ✔
Click for More Details
Option A: Adiabatic
Option B: Isothermal
Option C: Isometric
Option D: None of these
Correct Answer: Isothermal ✔
Click for More Details
Option A: +ve
Option B: -ve
Option C: 0
Option D: Either of the above three; depends on the nature of refrigerant
Correct Answer: 0 ✔
Click for More Details
Option A: A = H – TS
Option B: A = E – TS
Option C: A = H + TS
Option D: None of these
Correct Answer: B. A = E – TS ✔
Click for More Details
Option A: Fugacity
Option B: Activity co-efficient
Option C: Free energy
Option D: None of these
Correct Answer: None of these ✔
Click for More Details
Option A: Isothermal
Option B: Adiabatic
Option C: Isentropic
Option D: None of these
Correct Answer: Isothermal ✔
Click for More Details
Option A: Heating occurs
Option B: Cooling occurs
Option C: Pressure is constant
Option D: Temperature is constant
Correct Answer: Heating occurs ✔
Click for More Details
Option A: No
Option B: Any real
Option C: Only ideal
Option D: Both B. and C.
Correct Answer: Only ideal ✔
Click for More Details
Option A: More stable
Option B: Less stable
Option C: Not at all stable (like nascent O2)
Option D: Either more or less stable; depends on the compound
Correct Answer: More stable ✔
Click for More Details
Option A: Pressure
Option B: Temperature
Option C: Both A. & B.
Option D: Neither A. nor B.
Correct Answer: Temperature ✔
Click for More Details
Option A: Sublimation
Option B: Fusion
Option C: Transition
Option D: Vaporisation
Correct Answer: Transition ✔
Click for More Details
Option A: Volume of the liquid phase is negligible compared to that of vapour phase
Option B: Vapour phase behaves as an ideal gas
Option C: Heat of vaporisation is independent of temperature
Option D: All A , B. & C.
Correct Answer: D. All A , B. & C. ✔
Click for More Details
Option A: Directly proportional
Option B: Inversely proportional
Option C: Equal
Option D: None of these
Correct Answer: Directly proportional ✔
Click for More Details
Option A: By throttling
Option B: By expansion in an engine
Option C: At constant pressure
Option D: None of these
Correct Answer: By throttling ✔
Click for More Details
Option A: Isothermal
Option B: Adiabatic
Option C: Isentropic
Option D: Polytropic
Correct Answer: Isentropic ✔
Click for More Details
Option A: 0°C
Option B: 273°C
Option C: 100°C
Option D: -273°C
Correct Answer: 273°C ✔
Click for More Details
A system is said to be at equilibrium, if the entropy of the system has reached __________ value?
Option A: Minimum
Option B: Zero
Option C: Maximum
Option D: None of these
Correct Answer: Maximum ✔
Click for More Details
Option A: Escaping tendencies of the same substance in different phases of a system
Option B: Relative volatility of a mixture of two miscible liquids
Option C: Behaviour of ideal gases
Option D: None of these
Correct Answer: Escaping tendencies of the same substance in different phases of a system ✔
Click for More Details
Option A: Temperature
Option B: Pressure
Option C: Volume
Option D: Entropy
Correct Answer: Pressure ✔
Click for More Details
Option A: Closed
Option B: Open
Option C: Isolated
Option D: Non-thermodynamic
Correct Answer: Open ✔
Click for More Details
Option A: Decreases
Option B: Increases
Option C: Remain same
Option D: Decreases linearly
Correct Answer: Increases ✔
Click for More Details
Option A: Pressure vs. enthalpy
Option B: Pressure vs. volume
Option C: Enthalpy vs. entropy
Option D: Temperature vs. entropy
Correct Answer: Enthalpy vs. entropy ✔
Click for More Details
Option A: Logarithmic
Option B: Arithmetic
Option C: Geometric
Option D: Harmonic
Correct Answer: Geometric ✔
Click for More Details
As pressure approaches zero, the ratio of fugacity to pressure (f/P) for a gas approaches__________?
Option A: Zero
Option B: Unity
Option C: Infinity
Option D: An indeterminate value
Correct Answer: Unity ✔
Click for More Details
Option A: Process must be isobaric
Option B: Temperature must decrease
Option C: Process must be adiabatic
Option D: Both B. and C.
Correct Answer: D. Both B. and C. ✔
Click for More Details
Option A: Heat
Option B: Momentum
Option C: Energy
Option D: Work
Correct Answer: Energy ✔
Click for More Details
Option A: Direction of energy transfer
Option B: Reversible processes only
Option C: Irreversible processes only
Option D: None of these
Correct Answer: Direction of energy transfer ✔
Click for More Details
Option A: Less
Option B: More
Option C: Same
Option D: Dependent on climatic conditions
Correct Answer: Less ✔
Click for More Details
Option A: Is zero
Option B: Increases
Option C: Decreases whereas the entropy increases
Option D: And entropy both decrease
Correct Answer: Decreases whereas the entropy increases ✔
Click for More Details
Option A: Chemical potential
Option B: Fugacity
Option C: Both A. and B
Option D: Neither A. nor B
Correct Answer: C. Both A. and B ✔
Click for More Details
Option A: Temperature
Option B: Pressure
Option C: Composition
Option D: All (A), B. and (C)
Correct Answer: D. All (A), B. and (C) ✔
Click for More Details
Option A: Isometric
Option B: Polytropic
Option C: Isentropic
Option D: Isobaric
Correct Answer: Polytropic ✔
Click for More Details
Option A: Contracts
Option B: Expands
Option C: Has same volume
Option D: May contract or expand
Correct Answer: Contracts ✔
Click for More Details
The work done in isothermal compression compared to that in adiabatic compression will be__________?
Option A: Less
Option B: More
Option C: Same
Option D: More or less depending upon the extent of work done
Correct Answer: More ✔
Click for More Details
Option A: Isothermal
Option B: Adiabatic
Option C: Both A. & B
Option D: Neither A. nor B
Correct Answer: C. Both A. & B ✔
Click for More Details
Option A: Virial co-efficients are universal constants
Option B: Virial co-efficients ‘B’ represents three body interactions
Option C: Virial co-efficients are function of temperature only
Option D: For some gases, Virial equations and ideal gas equations are the same
Correct Answer: Virial co-efficients are function of temperature only ✔
Click for More Details
Option A: 0
Option B: 1
Option C: y = 1.44
Option D: 1.66
Correct Answer: 0 ✔
Click for More Details
Option A: Air cycle
Option B: Carnot cycle
Option C: Ordinary vapor compression cycle
Option D: Vapor compression with a reversible expansion engine
Correct Answer: Carnot cycle ✔
Click for More Details
Option A: Oxygen
Option B: Nitrogen
Option C: Air
Option D: Hydrogen
Correct Answer: Hydrogen ✔
Click for More Details
Option A: Latent heat of vaporisation
Option B: Chemical potential
Option C: Molal boiling point
Option D: Heat capacity
Correct Answer: Chemical potential ✔
Click for More Details
Option A: μ = (∂P/∂T)H
Option B: μ = (∂T/∂P)H
Option C: μ = (∂E/∂T)H
Option D: μ = (∂E/∂P)H
Correct Answer: μ = (∂T/∂P)H ✔
Click for More Details
Option A: Enthalpy remains constant
Option B: Entropy remains constant
Option C: Temperature remains constant
Option D: None of these
Correct Answer: Enthalpy remains constant ✔
Click for More Details
Option A: Kp2/Kp1 = – (ΔH/R) (1/T2 – 1/T1)
Option B: Kp2/Kp1 = (ΔH/R) (1/T2 – 1/T1)
Option C: Kp2/Kp1 = ΔH (1/T2 – 1/T1)
Option D: Kp2/Kp1 = – (1/R) (1/T2 – 1/T1)
Correct Answer: A. Kp2/Kp1 = – (ΔH/R) (1/T2 – 1/T1) ✔
Click for More Details
Option A: Water
Option B: Air
Option C: Evaporative
Option D: Gas
Correct Answer: Air ✔
Click for More Details
Option A: Van Laar
Option B: Margules
Option C: Gibbs-Duhem
Option D: Gibbs-Duhem-Margules
Correct Answer: Margules ✔
Click for More Details
Option A: Zero
Option B: Positive
Option C: Negative
Option D: None of these
Correct Answer: Negative ✔
Click for More Details
Option A: Freon-12
Option B: Ethylene
Option C: Ammonia
Option D: Carbon dioxide
Correct Answer: Ethylene ✔
Click for More Details
Option A: Zero
Option B: Negative
Option C: Very large compared to that for endothermic reaction
Option D: Not possible to predict
Correct Answer: Not possible to predict ✔
Click for More Details
Option A: 2.73
Option B: 28.3
Option C: 273
Option D: 283
Correct Answer: 28.3 ✔
Click for More Details
Option A: The energy change of a system undergoing any reversible process is zero
Option B: It is not possible to transfer heat from a lower temperature to a higher temperature
Option C: The total energy of system and surrounding remains the same
Option D: None of the above
Correct Answer: None of the above ✔
Click for More Details
Option A: Isothermal
Option B: Isobaric
Option C: Polytropic
Option D: Adiabatic
Correct Answer: Isothermal ✔
Click for More Details
Option A: Zero
Option B: Negative
Option C: More than zero
Option D: Indeterminate
Correct Answer: Zero ✔
Click for More Details
Option A: ds = 0
Option B: ds <0
Option C: ds > 0
Option D: ds = Constant
Correct Answer: ds > 0 ✔
Click for More Details
Option A: Only enthalpy change (ΔH) is negative
Option B: Only internal energy change (ΔE) is negative
Option C: Both ΔH and ΔE are negative
Option D: Enthalpy change is zero
Correct Answer: Both ΔH and ΔE are negative ✔
Click for More Details
Option A: Entropy
Option B: Temperature
Option C: Internal energy
Option D: Enthalpy
Correct Answer: Enthalpy ✔
Click for More Details
Option A: (p + a/V2)(V – b) = nRT
Option B: PV = nRT
Option C: PV = A + B/V + C/V2 + D/V3 + …
Option D: None of these
Correct Answer: C. PV = A + B/V + C/V2 + D/V3 + … ✔
Click for More Details
Option A: Entropy
Option B: Internal energy
Option C: Enthalpy
Option D: Gibbs free energy
Correct Answer: Gibbs free energy ✔
Click for More Details
Option A: Eutectic
Option B: Triple
Option C: Plait
Option D: Critical
Correct Answer: Triple ✔
Click for More Details
Option A: x
Option B: x + 1
Option C: x + 2
Option D: x + 3
Correct Answer: x ✔
Click for More Details
Option A: Two temperatures only
Option B: Pressure of working fluid
Option C: Mass of the working fluid
Option D: Mass and pressure both of the working fluid
Correct Answer: Two temperatures only ✔
Click for More Details
Option A: Non-uniformly
Option B: Adiabatically
Option C: Isobarically
Option D: Isothermally
Correct Answer: Isobarically ✔
Click for More Details
Option A: Minimum temperature attainable
Option B: Temperature of the heat reservoir to which a Carnot engine rejects all the heat that is taken in
Option C: Temperature of the heat reservoir to which a Carnot engine rejects no heat
Option D: None of these
Correct Answer: Temperature of the heat reservoir to which a Carnot engine rejects no heat ✔
Click for More Details
Option A: Adiabatic process
Option B: Endothermic reaction
Option C: Exothermic reaction
Option D: Process involving a chemical reaction
Correct Answer: Endothermic reaction ✔
Click for More Details
Option A: 0°C and 760 mm Hg
Option B: 15°C and 760 mm Hg
Option C: 20°C and 760 mm Hg
Option D: 0°C and 1 kgf/cm2
Correct Answer: 0°C and 760 mm Hg ✔
Click for More Details
Option A: √(2KT/m)
Option B: √(3KT/m)
Option C: √(6KT/m)
Option D: 3KT/m
Correct Answer: √(3KT/m) ✔
Click for More Details
Option A: System and surroundings pressure be equal
Option B: Friction in the system should be absent
Option C: System and surroundings temperature be equal
Option D: None of these
Correct Answer: Friction in the system should be absent ✔
Click for More Details
Option A: Increases with increase in pressure
Option B: Decreases with increase in temperature
Option C: Is independent of temperature
Option D: None of these
Correct Answer: None of these ✔
Click for More Details
Option A: Critical temperature
Option B: Melting point
Option C: Freezing point
Option D: Both B. and C
Correct Answer: D. Both B. and C ✔
Click for More Details
Option A: Only ΔE = 0
Option B: Only ΔH =0
Option C: ΔE = ΔH = 0
Option D: dQ = dE
Correct Answer: ΔE = ΔH = 0 ✔
Click for More Details
Option A: Is the most efficient of all refrigeration cycles
Option B: Has very low efficiency
Option C: Requires relatively large quantities of air to achieve a significant amount of refrigeration
Option D: Both B. and C
Correct Answer: D. Both B. and C ✔
Click for More Details
Option A: Free energy
Option B: Entropy
Option C: Refractive index
Option D: None of these
Correct Answer: Refractive index ✔
Click for More Details
Option A: Ethyl chloride or methyl chloride
Option B: Freon-12
Option C: Propane
Option D: NH3 or CO2
Correct Answer: Ethyl chloride or methyl chloride ✔
Click for More Details
Option A: Infinity
Option B: Unity
Option C: Constant
Option D: Negative
Correct Answer: Constant ✔
Click for More Details
Option A: A gas may have more than one inversion temperatures
Option B: The inversion temperature is different for different gases
Option C: The inversion temperature is same for all gases
Option D: The inversion temperature is the temperature at which Joule-Thomson co-efficient is infinity
Correct Answer: The inversion temperature is different for different gases ✔
Click for More Details
Option A: 5.2
Option B: 6.2
Option C: 0.168
Option D: Data insufficient, can’t be found out
Correct Answer: 5.2 ✔
Click for More Details
Option A: Reaction mechanism
Option B: Calculation of rates
Option C: Energy transformation from one form to another
Option D: None of these
Correct Answer: Energy transformation from one form to another ✔
Click for More Details