Time & Distance MCQs for Entry Test with Answers and Explanations [PDF]

A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the joɡɡer?

Option A: 3.6 sec

Option B: 18 sec

Option C: 36 sec

Option D: 72 sec

Correct Answer: 36 sec ✔

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Two trains are moving in opposite directions 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is_________?

Option A: 36

Option B: 45

Option C: 48

Option D: 49

Correct Answer: 48 ✔

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A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of

Option A: 120

Option B: 260

Option C: 240

Option D: 220

Correct Answer: 240 ✔

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A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

Option A: 80 Sec

Option B: 89 Sec

Option C: 90 Sec

Option D: 95 Sec

Correct Answer: 89 Sec ✔

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A man goes to his office from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming, what is the distance between his house and office?

A. 3 km
B. 4 km
C. 5 km
D. 6 km

Correct Answer: D. 6 km ✔

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A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

A. 121 km
B. 242 km
C. 224 km
D. 112 km

Correct Answer: C. 224 km ✔

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A man covers a distance of 20 km in 3.5 hours partly by running and partly by walking. If he walks at 4 kmph and runs at 10 kmph, find the distance he covers by walking.

A. 10 km
B. 8 km
C. 12 km
D. 9 km

Let the distance covered by walking be x km
the distance covered by running be (20-x) km Time for walking + time for running = 3.5 hours (x/4)+[(20-x)/10]=3.5 Solving,
5x+40-2x = 70
3x=30
x=10km

Correct Answer: A. 10 km ✔

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Rayan crosses a 400m bridge in 3 minutes. What is speed?

A. 133.33 kmph
B. 1.33 kmph
C. 4 kmph
D. 8 kmph

He crosses 0.4 km in 3/60th of an hour. Speed = 0.4/(1/20) = 8 kmph

Correct Answer: D. 8 kmph ✔

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Two bikes start at the same time from two destination 300 km apart and travel towards each other. If they cross each other at a distance of 130 km from one of the destination, what is the ratio of their speeds?

A. 17:13
B. 17:30
C. 13:30
D. None of these

Correct Answer: A. 17:13 ✔

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How much time does a train 125 metres long running at 60 km/hr take to pass a pole?

A. 6s
B. 2.08s
C. 7.5s
D. 8s

60 km/hr = 60 * 5/18 = 16.67 m/s
Speed = distance/time; v = d/t
16.67 = 125/t
t = 7.5s

Correct Answer: C. 7.5s ✔

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Walking 6/7th of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance?

A. 1 hr 42 min
B. 1 hr
C. 2 hr
D. 1 hr 12 min

New speed = 6/7 of usual speed
Speed and time are inversely proportional.
Hence new time = 7/6 of usual time
Hence, 7/6 of usual time – usual time = 12 minutes
=> 1/6 of usual time = 12 minutes
=> usual time = 12 x 6 = 72 minutes
= 1 hour 12 minutes

Correct Answer: D. 1 hr 12 min ✔

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Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

A. 12
B. 11
C. 10
D. 9

speed of the bus excluding stoppages = 54 kmph
speed of the bus including stoppages = 45 kmph
Loss in speed when including stoppages = 54 – 45 = 9kmph
=> In 1 hour, bus covers 9 km less due to stoppages
Hence, time that the bus stop per hour = time taken to cover 9 km

=distance/speed=9/54 hour=1/6 hour = 60/6 min=10 min

Correct Answer: C. 10 ✔

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There are 21 poles with a constant distance between each pole. A car takes 30 seconds to reach the 16th pole. How long does it take to reach the last pole?

A. 39 seconds
B. 40 seconds
C. 39.38 seconds
D. 39.5 seconds

The first pole is crossed at the zeroth second. The timer starts after the car crosses the first pole. Let the distance between each pole be x m. To reach the 16th pole, the distance travelled by the car is 15x. The speed of the car is 15x/30 = x/2 m/s To reach the 21st pole, it has to travel a distance of 20x. Time taken
= 20x÷(x/2)
= 40 seconds

Correct Answer: B. 40 seconds ✔

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A person walking at 5/6th of his usual speed is 40 minutes late to his office. What is his usual travel time to his office?

A. 3 hours 20 minutes
B. 3 hours 15 minutes
C. 3 hours 30 minutes
D. 3 hours

Let his usual speed be x kmph, the distance to his office be y km and his usual travel time be t hrs. y = xt = (5/6)x * (t+(40/60)) Solving the equation,
t = 3.33 hrs = 3 hrs 20 minutes

Correct Answer: A. 3 hours 20 minutes ✔

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A Man travelled a distance of 61 km in 9 hours. He travelled partly on foot at 4 km/hr and partly on bicycle at 9 km/hr. What is the distance travelled on foot?

A. 12 km
B. 14 km
C. 16 km
D. 18 km

Correct Answer: C. 16 km ✔

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A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

A. 8.2
B. 4.2
C. 6.1
D. 7.2

Correct Answer: D. 7.2 ✔

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Walking at 80% of his usual speed, a man is 10 mins late to his office. Find the usual time taken by hime to reach his office.

A. 20 minutes
B. 30 minutes
C. 40 minutes
D. 50 minutes

Let his
usual speed be x kmph
usual travel time be t hours
distance to office be d km d=xt d=(0.8x)*[t+(10/60)] xt=0.8xt+(2x/15) Solving,
t=40 minutes

Correct Answer: C. 40 minutes ✔

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At 10 a.m. two trains started traveling toward each other from stations 287 miles apart. They passed each other at 1:30 p.m. the same day. If the average speed of the faster train exceeded the average speed of the slower train by 6 miles per hour, which of the following represents the speed of the faster train, in miles per hour?

A. 38
B. 40
C. 44
D. 48

Let the speed of the faster train be x miles per hour and
the distance travelled by it when it meets the slower train be y miles. Time taken by the faster train to cover y miles
= Time taken by the slower train to cover (287-y) miles
= 3.5 hours (y/x) = (287-y)/(x-6) = 3.5 Solving, x = 44 miles/hr

Correct Answer: C. 44 ✔

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Three towns X, Y, and Z are on a river which flows uniformly. Y is equidistant from X and Z. If a boats man rows from X to Y and back in 10 hours and X to Z in 4 hours, find the ratio of speed of the boats man in still water to the speed of the current.

A. 2:5
B. 5:3
C. 3:5
D. 1:2

X ———— Y ———— Z
If ‘d’ is the distance between X and Y, then ‘d’ is the distance between Y and Z.
Now the total time for the batsman to row from X to Z is 4 hours. Therefore, time to row from X to Y is 2 hours.
Also the time for the boats man to row from X to Y and back is 10 hours. Hence, time required to row from Y to X is 8 hours.
If, a: speed of boats man in still water
b: speed of the river
d/(a + b) = 2; d/(a – b) = 8
2*(a + b) = 8*(a – b)
a + b = 4a – 4b
3a = 5b
a:b = 5:3

Correct Answer: B. 5:3 ✔

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A and B go cycling in the same direction with speeds of 6 km/hr and 12 km/hr. A car from behind passes them in 9 and 10 seconds respectively. What is the speed of the car?

A. 22 km/hr
B. 33 km/hr
C. 66 km/hr
D. 44 km/hr

The relative speed of A and B is 6 km/hr = 1.67 m/s
As the car passes A after 10s, the distance between A and B after 10s (i.e. at 11th second) is the distance covered by car in 1 second.
Therefore, at t = 11, d = 1.67 * 11
d = 18.33 m
v = d/t = 18.33/1 = 18.33m/s
v = 66 km/hr

Correct Answer: C. 66 km/hr ✔

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A car travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour?

A. 70.24 km/hr
B. 74. 24 km/hr
C. 71.11 km/hr
D. 72.21 km/hr

Correct Answer: C. 71.11 km/hr ✔

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A man takes 5 hours 45 min in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways is_________?

A. 11 hrs
B. 8 hrs 45 min
C. 7 hrs 45 min
D. 9 hts 20 min

Given that time taken for riding both ways will be 2 hours lesser than
the time needed for waking one way and riding back
From this, we can understand that
time needed for riding one way = time needed for waking one way – 2 hours
Given that time taken in walking one way and riding back = 5 hours 45 min
Hence The time he would take to walk both ways = 5 hours 45 min + 2 hours = 7 hours 45 min

Correct Answer: C. 7 hrs 45 min ✔

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In a journey of 24 miles, two thirds of the distance was travelled with a speed of 40 mph and the remaining with 60 mph. How much time did the journey take?

A. 14.4 minutes
B. 20 minutes
C. 28.8 minutes
D. 32 minutes

(2/3)*24=16 miles Time taken to cover the first 16 miles
= (16/40) hours
= 24 minutes Time taken to cover the next 8 miles
= (8/60) hours
= 8 minutes Time taken for the entire journey
= 32 minutes

Correct Answer: D. 32 minutes ✔

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A man travels a distance of 2 km by walking at a speed of 6 km/hr. He returns back at a speed of 4 km/hr. What is his average speed?

A. 4.5 kmph
B. 4.8 kmph
C. 5 kmph
D. 5.1 kmph

Time taken for the forward journey
= 2/6 = (1/3) hrs Time taken for the return journey
= 2/4 = (1/2) hrs Total time = 5/6 hrs Average speed = 4/(5/6) = 24/5 = 4.8kmph

Correct Answer: B. 4.8 kmph ✔

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A man rows at a speed of 6 km/hr in still water. If the time taken to row a certain distance upstream is 4 times the time taken to row the same distance downstream, what is the speed of the river?

A. 1.8 km/hr
B. 3 km/hr
C. 3.6 km/hr
D. 4 km/hr

Let x be the speed of the river.
Ds = (6 + x) km/hr; Us = (6 – x) km/hr
If t hours is the time to row downstream then 4t hours is the time to row upstream.
(6 + x)*t = (6 – x)*4t
6 + x = 24 – 4x
x = 3.6 km/hr

Correct Answer: C. 3.6 km/hr ✔

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Two trains 140 metres and 120 metres are running in the same direction with speeds 40 kmph and 60 kmph respectively. In what time will the faster train pass the slower one?

A. 0.60 minutes
B. 0.36 minutes
C. 0.78 minutes
D. 0.42 minutes

Total distance = addition of length of the two trains = 140 + 120 = 260 metres
As the two trains are travelling in the same direction, their relative speed is:
v = | v1 – v2 | = | 40 – 60 | = 20 km/hr = 20*1000/60 = 1000/3 metres/min
t = 260/ 1000*3
t = 0.78 minutes

Correct Answer: C. 0.78 minutes ✔

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Yalmaz can cover a distance of 400 metres in 2 minutes. Rayan can cover 1 km in 300 seconds. Find the ratio of their speeds.

A. 2:5
B. 4:3
C. 1:2
D. 1:1

Rayan’s speed = 1000/300 = 3.33 m/s
Hence Ratio = 1:1

Correct Answer: D. 1:1 ✔

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If the ratio of the speeds of A and B to cover a distance of 200 m is 3:4, then the ratio of the time taken to cover the same distance is________?

A. 6:8
B. 3:7
C. 5:4
D. 4:3

If the ratio of the speeds of two objects is a:b, then the time taken by them to cover the same distance is
b:a Hence, the answer is 4:3

Correct Answer: D. 4:3 ✔

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A car can travel 360km with a ¾ full tank. How many km can it travel with a 2/3 full tank?

A. 400
B. 320
C. 240
D. 300

With a full tank, it can travel
360*4/3 = 480 km With 2/3 full tank, it can travel
480*2/3 = 320 km

Correct Answer: B. 320 ✔

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A boats man can row in still water at speed of 7 km/hr. It takes 6 hours more to travel the same distance in upstream than in downstream if the speed of the river is 3 km/hr. what is the distance between the two destinations?

A. 20 km
B. 40 km
C. 30 km
D. 10 km

x = 7 km/hr ; y = 3 km/hr
Ds = 10 km/hr ; Us = 4 km/hr
Distance (d) is same. Therefore, if time taken for downstream is t hours, the time for upstream is (t + 6) hours.
10*t = 4*(t + 6)
6t = 24 ; t = 4 hours
d = 10*4 = 40 km

Correct Answer: B. 40 km ✔

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If Afnan drives at 4/5th of his usual speed to his office, he is 6 minutes late. What is his usual time to reach his office?

A. 36
B. 24
C. 30
D. 18

Let t be his usual time to reach his office and v be his usual speed.
v = d/t ……….(d is the distance Afnan travels while going to his office)
vt = d
At v1 = 4v/5 ; t1 = t + 6
4v/5 = d/(t + 6)
4v/5* (t + 6) = d
4v/5* (t + 6) = vt
On solving we get,
t = 24 minutes

Correct Answer: B. 24 ✔

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Two boys starts from the same place walking at the rate of 5 kmph and 5.5 kmph respectively in the same direction. What time will they take to be 8.5 km apart?

A. 17 hr
B. 14 hr
C. 12 hr
D. 19 hr

Relative speed = 5.5 – 5 = .5 kmph (because they walk in the same direction)
distance = 8.5 km

time = distance/speed=8.5/.5=17 hr

Correct Answer: A. 17 hr ✔

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A cyclist covers a certain distance in 50 minutes at a speed of 24 kmph. To cover the same distance in 40 minutes, he should travel at a speed of__________?

A. 30 kmph
B. 27 kmph
C. 25 kmph
D. 20 kmph

Distance = 24*50/60 = 20 km New Speed = 20/(40/60)) = 30 kmph

Correct Answer: A. 30 kmph ✔

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Excluding stoppages, the average speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

A. 9
B. 10
C. 12
D. 20

Due to stoppages, the bus travels only 45 kms in an hour (9 kms less). To cover a distance of 9 km at a speed of 54 kmph, time taken
= 9/54 = 1/6 hrs = 10 mins.

Correct Answer: B. 10 ✔

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If a boat is rowed downstream for 50 km in 5 hours and upstream for 24 km in 6 hours, what is the speed of the boat and the river?

A. (7 , 3) km/hr
B. (6 , 4) km/hr
C. (10 , 4) km/hr
D. None of these

If x: speed of boats man in still water
y: speed of the river
Downstream speed (Ds) = x + y
Upstream speed (Us) = x – y
x = (Ds + Us) / 2
y = (Ds – Us) / 2
In the above problem Ds = 10 ; Us = 4
x = (10 + 4) / 2 = 14/2 = 7 km/hr
y = (10 – 4)/2 = 6/2 = 3 km/hr

Correct Answer: A. (7 , 3) km/hr ✔

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Taimoor left for his school at 6 am by foot and walked at the rate of 2 kmph. After reaching his school he found it was closed and immediately turned back and started walking back to his home at 3 kmph. If he reached his home at 9 am, find the distance between his school and his home.

A. 2.5 km
B. 7.2 km
C. 7 km
D. 3.6 km

Average speed of Taimoor = (2*2*3)/(2 + 3) = 2.4 km/hr
If d is he distance between the school and Taimoor’s home, then total distance walked by Taimoor = 2d, and the total time taken is 3 hours
2.4 = 2d/3
7.2 = 2d
d = 3.6 km

Correct Answer: D. 3.6 km ✔

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A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. What is the speed of the car?

A. 80 kmph
B. 102 kmph
C. 120 kmph
D. 140 kmph

Correct Answer: C. 120 kmph ✔

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A and B walk around a circular track. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. If they start at 8 a.m. from the same point in opposite directions, how many times shall they cross each other before 9.30 a.m.?

A. 5
B. 6
C. 7
D. 8

Relative speed = Speed of A + Speed of B (∴ they walk in opposite directions)
= 2 + 3 = 5 rounds per hour
=> They cross each other 5 times in 1 hour and 2 times in 1/2 hour
Time duration from 8 am to 9.30 am = 1.5 hour
Hence they cross each other 7 times before 9.30 am

Correct Answer: C. 7 ✔

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If a man walks at 6 kmph, he can reach his destination at 9:00 am. However, he walks a little slower and reaches only at 10:00 am. If the distance to his destination was 12 km, at what speed did he walk?

A. 5 kmph
B. 4 kmph
C. 4.5 kmph
D. 3 kmph

If he travels at 6 kmph,
time taken to reach = 12/6 = 2 hours But he takes 3 hours.
Speed = 12/3 = 4 kmph

Correct Answer: B. 4 kmph ✔

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In a race, a car travelled at a speed of 150 kmph. If it had travelled at 180 kmph, it would have completed the race before 3 minutes. Find the length of the track.

A. 50 km
B. 45 km
C. 40 km
D. 30 km

Correct Answer: B. 45 km ✔

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Asghar traveled from his house to his office at 10 km/hr and returned at rate of 9 km/hr. Rohit travelled through the same path both ways at 12 km/hr and took 10 minutes less than Asghar. What is the distance between Asghar’s house and his office?

A. 3000m
B. 7500m
C. 3750m
D. 7000m

Average speed for Raj is: v = (2*9*10)/(9+10) = 180/19 km/hr = 50/19 m/s
Average speed for Rohit = 12 km/hr = 10/3 m/s
Now, v = d/t
As d is same, v*t = constant.
Let, t be the time taken by Rohit in seconds. Hence, time taken by Raj is (t +600)s
50/19 * (t + 600) = 10/3 * t
150*(t + 600) = 190t
t = 2250s
Let d be the distance between the house and the office
2d = 2250 * 10/3
2d = 7500 m
d = 3750m

Correct Answer: C. 3750m ✔

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An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 5/3 hours, it must travel at a speed of:_________?

A. 660 km/hr
B. 680 km/hr
C. 700 km/hr
D. 720 km/hr

Distance = Speed x Time = 240 x 5 km
New time =5/3 hr

Hence, new speed = Distance/Time =240*5/5/3

=240×3=720 km/hr

Correct Answer: D. 720 km/hr ✔

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A man covered a certain distance at some speed. If he had moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. What is the the distance in km?

A. 36
B. 52
C. 41
D. 40

Correct Answer: D. 40 ✔

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A car gives a mileage of 20 km per liter of petrol when driven at a constant speed of 50 kmph but the mileage decreases by 10% when driven at a speed of 70 kmph. How many km can the car travel with 12 liters of petrol if it travels a speed of 70 kmph?

A. 216 km
B. 240 km
C. 228 km
D. 200 km

Correct Answer: A. 216 km ✔

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A car travels 50% faster than a bike. Both start at the same time from A to B. The car reaches 25 minutes earlier than the bike. If the distance from A to B is 100 km, find the speed of the bike.

A. 120 km
B. 100 km
C. 80 km
D. 75 km

Let the speed of the bike be x kmph. Then the speed of the car will be 3x/2 kmph. Time taken by the bike
t1 = 100/x Time taken by the bike
t2 = 100/(3x/2) t1 – t2 = 25/60 (100/x) – (100/(3x/2)) = 5/12 Solving the equation, x = 80 kmph

Correct Answer: C. 80 km ✔

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Two trains 120 miles apart travel towards each other. The 1st train travels at 70 mph while the 2nd at 50 mph. A bird starts flying from the location of the faster train towards the other train at 85 mph and when it reaches the slower train it turns back and flies in the other direction at the same speed. When it reaches the faster train it again turns around and repeats the same procedure again and again. When the train collide, how far will the bird have flown?

A. 85 miles
B. 70 miles
C. 50 miles
D. 120 miles

Correct Answer: A. 85 miles ✔

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A man travels from A to B at a speed of 30 kmph and returns with a speed of 60 kmph. What is the average speed of the man?

A. 47.5
B. 50
C. 45
D. 40

Correct Answer: D. 40 ✔

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A man rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. What is his average speed for the entire trip approximately?

A. 11.2 kmph
B. 10 kmph
C. 10.2 kmph
D. 10.8 kmph

Correct Answer: D. 10.8 kmph ✔

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A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. What is the actual speed of the car?

A. 30 km/hr
B. 35 km/hr
C. 25 km/hr
D. 40 km/hr

Correct Answer: B. 35 km/hr ✔

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Atif and Bilal, 110 km apart, start cycling towards each other. If Atif covers a distance of 6 km to Bilal’s 5 km, how far will Atif have travelled when they meet?

A. 66 km
B. 55 km
C. 50 km
D. 60 km

Correct Answer: D. 60 km ✔

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Danish his car at a speed of 120 kmph for the first 2 hours and then at a speed of 100 kmph for the next half an hour. Find the distance covered by him during the entire journey.

A. 300 km
B. 290 km
C. 250 km
D. 240 km

Total distance = (120*2) + (100*(1/2)) = 290 km

Correct Answer: B. 290 km ✔

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Barkat is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph; he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M. ?

A. 8 kmph
B. 11 kmph
C. 12 kmph
D. 14 kmph

Correct Answer: C. 12 kmph ✔

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A train when moves at an average speed of 40 kmph, reaches its destination on time. When its average speed becomes 35 kmph, then it reaches its destination 15 minutes late. Find the length of journey.

A. 30 km
B. 40 km
C. 70 km
D. 80 km

Correct Answer: C. 70 km ✔

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A boy goes to his school from his house at a speed of 3 km / hr and returns at a speed of 2 km / hr. If he takes 5 hours in going and coming, the distance between his house and school is :__________?

A. 5 km
B. 5.5 km
C. 6 km
D. 6.5 km

Average speed = ( 2 X 3 X 2/3 + 2 ) km/ hr = 12/5 km/ hr. Distance travelled = ( 12/5 X 5 )km = 12 km. So Distance between house and school = ( 12/2 )km = 6 km.

Correct Answer: C. 6 km ✔

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An express train travelled at an average speed of 100 km / hr, stopping for 3 minutes after every 75 km. How long did it take to reach its destination 600 km from the starting point ?

A. 6 hrs 21 min
B. 6 hrs 24 min
C. 6 hrs 27 min
D. 6 hrs 30 min

Time taken to cover 600 km = ( 600/100 ) hrs = 6 hrs. Number of stoppages = ( 600/75 – 1 ) = 7 Total time of stoppage = (3 x 7) min = 21 min. Hence, total time taken = 6 hrs 21 min.

Correct Answer: A. 6 hrs 21 min ✔

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A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start in the same direction from the same point at 7.30 a.m. They shall first cross each other at :__________?

A. 7.42 a.m.
B. 7.48 a.m.
C. 8.10 a.m.
D. 8.30 a.m.

Correct Answer: A. 7.42 a.m. ✔

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A can complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km / hr and second half at the rate of 24 km / hr. Find the total journey in km.

A. 220 km
B. 224 km
C. 230 km
D. 234 km

Correct Answer: B. 224 km ✔

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A car is running at a speed of 108 kmph. What distance will it cover in 15 seconds ?

A. 45 metres
B. 55 metres
C. 450 metres
D. Cannot be determined

Correct Answer: C. 450 metres ✔

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A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km /hr, the time taken by it to cover the same distance will be :__________?

A. 10 min
B. 11 min 20 sec
C. 13 min
D. 13 min 20 sec

Speed = (10 X 60/12 ) km/hr = 50 km/hr. New speed = (50 – 5) km / hr = 45 km /hr. So Time taken = ( 10/45 ) hr = ( 2/9X 60 )min 131/3 min = 13 min 20 sec.

Correct Answer: D. 13 min 20 sec ✔

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Two automobiles are 150 kilometers apart and traveling toward each other. One automobile is moving at 60km/h and the other is moving at 40km/h mph. In how many hours will they meet?

Option A: 2.5

Option B: 2.0

Option C: 1.75

Option D: 1.5

Correct Answer: 1.5 ✔

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