Option A: Above the proportional limit a material function in a plastic manner, while below the proportional limit it behaves as an elastic
Option B: Above the proportional limit a material functions in an elastic manner, while below the proportional limit it behaves as an plastic
Option C: Either A or B
Option D: Neither A or B
Correct Answer: Above the proportional limit a material function in a plastic manner, while below the proportional limit it behaves as an elastic ✔
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Option A: Type I and Type II gold can be heat treated and annealed
Option B: Type III and Type IV gold can be heat treated and annealed
Option C: Type I and IV gold can be heat treated and annealed
Option D: All the type of gold can be heat treated and annealed
Correct Answer: Type III and Type IV gold can be heat treated and annealed ✔
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Option A: Methyl methacrylate
Option B: Benzoyl peroxide
Option C: Hydroquinone
Option D: D-methyl paratolouidine
Correct Answer: Methyl methacrylate ✔
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Option A: B.P of water
Option B: < B.P of water
Option C: Equal of BP of water
Option D: Is at normal room temperature
Correct Answer: B.P of water ✔
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Option A: Higher solubility in saliva
Option B: Lower modulus of elasticity
Option C: Esthetic excellence
Option D: Lower thermal co-efficient of expansion
Correct Answer: Lower thermal co-efficient of expansion ✔
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Option A: Resin
Option B: Filler
Option C: Resin & Filler
Option D: None
Correct Answer: Resin ✔
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Option A: Anterior restorations
Option B: Temporary bridges
Option C: Denture base
Option D: All of the above
Correct Answer: All of the above ✔
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Option A: Cold water
Option B: Hot water
Option C: Under tap water
Option D: Under vacuum pressure
Correct Answer: Under vacuum pressure ✔
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Option A: A prolonged curing cycle
Option B: Lack of sufficient pressure applied to flask
Option C: Insufficient acrylic resin monomer
Option D: Prolonged bench cooling after curing
Correct Answer: Lack of sufficient pressure applied to flask ✔
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Option A: Glycol dimetharylate
Option B: Benzoyl peroxide
Option C: N-para toluidine
Option D: Methyl methacrylate
Correct Answer: Glycol dimetharylate ✔
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Option A: To prevent polymerization during storage
Option B: To initiate release of free radicalls
Option C: To enable polymerization reaction at room temperature
Option D: All of the above
Correct Answer: To prevent polymerization during storage ✔
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Option A: Diketone-amine
Option B: Organic acid-metal oxide
Option C: Organic acid-peroxide
Option D: Peroxide-amine
Correct Answer: Diketone-amine ✔
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Option A: A filled resin
Option B: Colloidal silica
Option C: Gold alloy
Option D: Wax
Correct Answer: A filled resin ✔
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1. Methacrylate
2. Ethylmethacrylate
3. Methyl ethyl methacrylate
4. Polymethylmethacrylate
Correct Answer: 1. Methacrylate ✔
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Option A: Iritis
Option B: Cataract
Option C: Conjunctivitis
Option D: Retinal damage
Correct Answer: Retinal damage ✔
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Option A: Covalent bond
Option B: Ionic bond
Option C: Mechanical
Option D: Vanderval forces
Correct Answer: Mechanical ✔
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Option A: Plastic
Option B: Stainless steel
Option C: Iron
Option D: None of the above
Correct Answer: Plastic ✔
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Option A: Excessive expansion
Option B: Low impact strength
Option C: Excessive shrinkage
Option D: Excessive brittleness
Correct Answer: Excessive shrinkage ✔
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Option A: UV light
Option B: Visible light
Option C: Infrared light
Option D: Diketone
Correct Answer: UV light ✔
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Option A: Packing at dough stage
Option B: Curing at 160°F for 9 hrs
Option C: Inadequate pressure
Option D: All of the above
Correct Answer: All of the above ✔
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Option A: Localised Shrinkage porosity
Option B: Gas inclusion porosity
Option C: Micro porosity
Option D: Surface porosity
Correct Answer: Micro porosity ✔
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Option A: 0.05 to 0.04mm
Option B: 0.5 to 1.0 microns
Option C: 0.01 to 0.1 microns
Option D: 0.3 to 0.4mm
Correct Answer: 0.01 to 0.1 microns ✔
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Option A: Composite
Option B: Complex material
Option C: Combined
Option D: Compound
Correct Answer: Composite ✔
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Option A: Amalgam
Option B: Silicate cement
Option C: Gold alloy
Option D: Acrylic resin
Correct Answer: Acrylic resin ✔
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Option A: Heat
Option B: Visible light
Option C: Chemicals
Option D: Lasers
Correct Answer: Visible light ✔
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Option A: Prevent galvanic action
Option B: Are practically insoluble in oral fluids
Option C: Adapt to the walls of the cavity better
Option D: Have a higher coefficient of thermal expansion
Correct Answer: Are practically insoluble in oral fluids ✔
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Option A: To prevent the porosity
Option B: To prevent warpage
Option C: To prevent volume expansion
Option D: All of the above
Correct Answer: To prevent the porosity ✔
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Option A: Increase the surface area
Option B: Permit chemical bonding between resin and enamel
Option C: Create surface irregularities in enamel for better mechanical retention of resin
Option D: Condition the tooth surface for better wetting
Correct Answer: Permit chemical bonding between resin and enamel ✔
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Option A: Glass ionomer restoratives
Option B: Hybrid resin composites
Option C: Microfilled resin composites
Option D: Macrofilled resin composites
Correct Answer: Microfilled resin composites ✔
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Option A: Microfilled resin
Option B: Macrofilled resin
Option C: Hybrid
Option D: Light cure activated
Correct Answer: Microfilled resin ✔
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Option A: Composites
Option B: Unfilled resins
Option C: Amalgam
Option D: Polycarboxylate
Correct Answer: Unfilled resins ✔
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Option A: Nd:YAG
Option B: CO2
Option C: ER:YAG
Option D: Argon
Correct Answer: Argon ✔
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Option A: Covalent bonds
Option B: sonic bonds
Option C: Vander Wall’s Forces
Option D: Hydrogen Bonds
Correct Answer: Covalent bonds ✔
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Option A: Biological properties
Option B: Thermal properties
Option C: Mechanical properties
Option D: Esthetic properties
Correct Answer: Thermal properties ✔
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Option A: Parabane
Option B: Ligane
Option C: Silane
Option D: Chelane
Correct Answer: Silane ✔
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Option A: 4th generation bonding agents
Option B: Separate etching step not required
Option C: Separate etching step is still required
Option D: Contains only primer
Correct Answer: Separate etching step is still required ✔
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Option A: Decrease micro leakage
Option B: Decrease polymerization shrinkage
Option C: Decrease coefficient of thermal expansion
Option D: Decrease porosity in restorative material
Correct Answer: Decrease micro leakage ✔
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Option A: Microwave-activated resins
Option B: Tertiary amine-activated resins
Option C: Light activated resins
Option D: Heat activated resins
Correct Answer: Light activated resins ✔
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Option A: 1% by volume 0.23% by weight
Option B: 10% by volume 0.23% by weight
Option C: 0.1% by volume 0.23% by weight
Option D: None of the above
Correct Answer: 1% by volume 0.23% by weight ✔
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Option A: Knoop hardness number 18 to 20
Option B: Tensile strength of 60 MPa
Option C: Density of 1.13 g/cm3
Option D: Modulus of elasticity of 3.4 GPa
Correct Answer: Modulus of elasticity of 3.4 GPa ✔
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Option A: Better control over placement
Option B: Enhance and concentrate the action of acid
Option C: Helps in visualization while placement
Option D: None of the above
Correct Answer: Better control over placement ✔
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Option A: 25°C
Option B: 37°C
Option C: 50°C
Option D: 60°C
Correct Answer: 60°C ✔
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Option A: 10 um – 20 um
Option B: 3 um – 9 um
Option C: 50 um – 110 um
Option D: 200 um – 250 um
Correct Answer: A. 10 um – 20 um ✔
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Option A: 3:1
Option B: 4:1
Option C: 10:1
Option D: 5:1
Correct Answer: 3:1 ✔
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Option A: 0.2% to 0.5%
Option B: 2% to 5%
Option C: 0.3% to 0.5%
Option D: 2% to 5%
Correct Answer: 2% to 5% ✔
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Option A: Removes smear layer
Option B: Increases surface energy of dentin
Option C: Forms a thin resin layer over exposed collagen fibrils
Option D: Helps in bonding with composite
Correct Answer: Removes smear layer ✔
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Option A: Step-growth polymerization
Option B: Addition polymerization
Option C: Condensation polymerization
Option D: Copolymerization
Correct Answer: Copolymerization ✔
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Option A: Internal color
Option B: Tissue compability
Option C: Surface hardness
Option D: Craze resistance
Correct Answer: Craze resistance ✔
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Option A: Thermal changes
Option B: Thickness of the resin
Option C: Lack of temperature
Option D: Packing past the dough stage
Correct Answer: Thermal changes ✔
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Option A: Distortion
Option B: Porosity
Option C: Inhomogeneous colour
Option D: Increased strength
Correct Answer: Porosity ✔
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Option A: Quartz
Option B: Silicates
Option C: Zinc particles
Option D: Aluminium
Correct Answer: Quartz ✔
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Option A: Poor colour stability
Option B: Less polymerization shrinkage
Option C: Increase in vertical dimension
Option D: Decrease in vertical dimension
Correct Answer: Increase in vertical dimension ✔
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Option A: 300 mw/sm2
Option B: 350 mw/cm2
Option C: 400 mw/cm2
Option D: 450 mw/cm2
Correct Answer: 300 mw/sm2 ✔
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Option A: Tertiary amine
Option B: Benzoyl peroxide free radical
Option C: Hydroquinone
Option D: Methyl ether
Correct Answer: Benzoyl peroxide free radical ✔
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Option A: Throughout the denture
Option B: Near the borders
Option C: In the thickest part
Option D: On the denture surface
Correct Answer: In the thickest part ✔
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Option A: Low compressive strength
Option B: High abrasive resistance
Option C: High water absorption
Option D: High polymerization shrinkage
Correct Answer: High abrasive resistance ✔
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Option A: Poor colour stability
Option B: Less polymerization shrinkage
Option C: Increase in vertical dimension
Option D: Decrease in vertical dimension
Correct Answer: Increase in vertical dimension ✔
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Option A: Thermal changes
Option B: Thickness of the resin
Option C: Lack of temperature
Option D: Packing past the dough stage
Correct Answer: Thermal changes ✔
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Option A: Distortion
Option B: Porosity
Option C: Inhomogeneous colour
Option D: Increased strength
Correct Answer: Porosity ✔
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Option A: Quartz
Option B: Silicates
Option C: Zinc particles
Option D: Aluminium
Correct Answer: Quartz ✔
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Option A: Zinc oxide
Option B: Methyl methacrylate
Option C: Phosphoric acid
Option D: Eugenol
Correct Answer: Phosphoric acid ✔
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Option A: Addition of grain refining agents
Option B: Addition of difunctional monomers
Option C: Increasing the amount of heat required for linear polymerization
Option D: Incorporation of terminating agents
Correct Answer: Addition of difunctional monomers ✔
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Option A: Should be held at a millimeter distance from the restoration
Option B: Need no protection while in use
Option C: Will cure composite upto a depth of 5 millimeter thickness
Option D: Is fiber optic
Correct Answer: Should be held at a millimeter distance from the restoration ✔
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Option A: Toluidine
Option B: Quaternary ammonium compound
Option C: Benzoyl peroxide
Option D: Tertiary amine
Correct Answer: Tertiary amine ✔
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Option A: Amalgam alloy
Option B: Unfilled resin
Option C: Composite resin
Option D: Direct filling gold
Correct Answer: Unfilled resin ✔
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Option A: 1925
Option B: 1937
Option C: 1951
Option D: 1956
Correct Answer: 1937 ✔
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Option A: Increased thermal conductivity
Option B: Decreased wear resistance
Option C: Decreased thermal conductivity
Option D: None of the above
Correct Answer: Decreased wear resistance ✔
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Option A: 3% to 5%
Option B: 8% to 10%
Option C: 0.2% to 0.5%
Option D: 0.6% to 0.8%
Correct Answer: 0.2% to 0.5% ✔
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Option A: Increases vertical dimension
Option B: Causes teeth to be shrunken in investment
Option C: Causes poor quality of colour
Option D: Causes fracture of denture
Correct Answer: Increases vertical dimension ✔
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Option A: Increasing the mechanical strength
Option B: Decreasing the coefficient of thermal expansion
Option C: Reducing the polymerization shrinkage
Option D: All of the above
Correct Answer: All of the above ✔
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Option A: Polymerization shrinkage is greater if bonded surface area is lesser than unbounded surface area
Option B: Polymerization shrinkage is high if within the enamel margins
Option C: Acid etching and priming will decrease polymerization shrinkage
Option D: Microleakage can occur because of polymerization shrinkage
Correct Answer: Polymerization shrinkage is greater if bonded surface area is lesser than unbounded surface area ✔
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Option A: It can be finished smoothly
Option B: It has a low degree of flow
Option C: It’s non-irritation to pulp
Option D: It’s wear resistant is high
Correct Answer: It can be finished smoothly ✔
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Option A: Only Hydrophobic component
Option B: Only Hydrophilic component
Option C: Hydrophobic and hydrophilic component
Option D: Lyophillic and lyophobic component
Correct Answer: Hydrophobic and hydrophilic component ✔
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Option A: TEGDMA
Option B: BIS-GMA
Option C: Ti02
Option D: None of the above
Correct Answer: Ti02 ✔
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Option A: Cold water
Option B: Hot water
Option C: Under pressure
Option D: In vaccum
Correct Answer: Hot water ✔
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Option A: 30 seconds
Option B: 60 seconds
Option C: 90 seconds
Option D: 120 seconds
Correct Answer: 30 seconds ✔
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No trail closure is necessary with which one of the technique during denture fabrication__________?
Option A: Compression moulding technique
Option B: Injection moulding technique
Option C: Fluid resin technique
Option D: Light cured technique
Correct Answer: Injection moulding technique ✔
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Option A: Adhesion of resin particles
Option B: Bonding between filler crystals
Option C: Bonding between filler and resin
Option D: Bonding between tooth and resin
Correct Answer: Bonding between tooth and resin ✔
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Option A: BIS GMA
Option B: Polymethyl methacrylate
Option C: Benzoin methyl ether
Option D: Silica filter
Correct Answer: BIS GMA ✔
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Option A: porosity
Option B: Shrinkage
Option C: Tooth breakage
Option D: Water absorption
Correct Answer: Shrinkage ✔
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Option A: Silica glass
Option B: Organic matrix
Option C: Barium glass and strontium glasses
Option D: Fluoride particles
Correct Answer: Barium glass and strontium glasses ✔
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Option A: Melts at 100°C
Option B: Softens at 100°C
Option C: Still requires heat for polymerization
Option D: Produces heat during polymerization
Correct Answer: Produces heat during polymerization ✔
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Option A: Thermal polymerization of acrylic
Option B: Chemical polymerization
Option C: Retarding the polymerization reaction
Option D: To inhibit the action of benzoyl peroxide
Correct Answer: Chemical polymerization ✔
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If curing occurs at temperature more than 100°C porosity results in which area of denture__________?
1. Hard thick central area
2. Thin Palatal area
3. Thin area of flanges
4. Porosity is uniformly distributed
Correct Answer: 1. Hard thick central area ✔
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Option A: The former have a lower molecular weight
Option B: The former have higher residual monomer content
Option C: The former are more porous
Option D: The former have greater transverse strength
Correct Answer: The former have greater transverse strength ✔
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Option A: Young’s modulus
Option B: Plastic strain
Option C: Elastic strain
Option D: Flexural strain
Correct Answer: Elastic strain ✔
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Option A: Slicate cement
Option B: Composite
Option C: GIC
Option D: Polycarboxylate
Correct Answer: GIC ✔
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Option A: Primary forces
Option B: Secondary forces
Option C: Cohesive forces
Option D: Ionic forces
Correct Answer: Cohesive forces ✔
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Option A: Reflector
Option B: Translucent
Option C: Transparent
Option D: Opaque
Correct Answer: Transparent ✔
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Option A: Complete wetting of surfaces
Option B: Rough surfaces between Adhesive & Adherent
Option C: Adherent and Adhesive molecules are tangent to each other
Option D: Irregularities present between Adherent surfaces
Correct Answer: Complete wetting of surfaces ✔
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Option A: Ductile materials
Option B: Flexible materials
Option C: Brittle materials
Option D: Malleable materials
Correct Answer: Brittle materials ✔
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Option A: Liquid should wet solid surface
Option B: Mechanical interlocking should be present
Option C: Should have high contact angle
Option D: None of the above
Correct Answer: Liquid should wet solid surface ✔
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Option A: Solid solution
Option B: Eutectic mixture
Option C: Peritectic mixture
Option D: Inter metallic compounds
Correct Answer: Solid solution ✔
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Option A: Grain
Option B: Nucleus
Option C: Stroma
Option D: None of the above
Correct Answer: Grain ✔
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Option A: Define and measure colour qualitatively
Option B: Define and measure physical properties of gold alloys
Option C: Evaluate brittleness of different alloys
Option D: Measures different colours quantitatively
Correct Answer: Measures different colours quantitatively ✔
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Option A: Inter atomic movement
Option B: Inter atomic imbalance
Option C: Arrangement of atoms
Option D: Arrangement of molecules
Correct Answer: Arrangement of atoms ✔
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Option A: Resilience
Option B: Maximum flexibility
Option C: Toughness
Option D: Elastic limit
Correct Answer: Maximum flexibility ✔
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Option A: Thixotropic
Option B: Pseudoplastic
Option C: Dilatant
Option D: Newton
Correct Answer: Dilatant ✔
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Option A: Greater ductility
Option B: Greater toughness
Option C: A higher modulus of elasticity
Option D: A higher modulus of elasticity
Correct Answer: More resistance to permanent deformation ✔
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