Physics MCQs

Option A: Increases

Option B: Decreases

Option C: Remains same

Option D: No effect

Correct Answer: Decreases ✔

Option A: Equal to D.C. value

Option B: More than D.C. value

Option C: Less than D.C. value

Option D: Zero

Correct Answer: B. More than D.C. value ✔

Option A: 2

Option B: 3

Option C: 4

Option D: 5

Correct Answer: 3 ✔

Option A: Step up transformer

Option B: Step down transformer

Option C: Three diodes in common

Option D: Triode vacuum tube

Correct Answer: Triode vacuum tube ✔

Option A: Non-inverting voltage at output

Option B: Reference voltage on the other

Option C: Virtual input

Option D: Output

Correct Answer: Reference voltage on the other ✔

Option A: A very high input impedance

Option B: A very low input impedance

Option C: A low output impedance

Option D: None of the above

Correct Answer: A very high input impedance ✔

Option A: That the emitter be heated

Option B: That the base be heated

Option C: That the collector be heated

Option D: None of the above

Correct Answer: None of the above ✔

Option A: 2

Option B: 3

Option C: 4

Option D: 5

Correct Answer: 5 ✔

Option A: A high gain amplifier

Option B: A high-power amplifier

Option C: A high resistance amplifier

Option D: A low resistance amplifier

Correct Answer: A high gain amplifier ✔

Option A: A digital waveform

Option B: An analogue waveform

Option C: Discrete waveform

Option D: None at all

Correct Answer: An analogue waveform ✔

Option A: The light emitting diodes

Option B: Photo diodes

Option C: Photo voltaic cell

Option D: Solar cells.

Correct Answer: Photo diodes ✔

Option A: Converter

Option B: A rectifier

Option C: Inverter

Option D: Oscillator

Correct Answer: Inverter ✔

Option A: The negative half cycle of A.C.

Option B: The positive half cycle of A.C.

Option C: The positive and negative half cycles

Option D: Either positive or negative half of A.C.

Correct Answer: The positive half cycle of A.C. ✔

Option A: The positive half cycle of input A.C.

Option B: The negative half cycle of input A.C.

Option C: The complete cycle of input A.C.

Option D: All of the above.

Correct Answer: C. The complete cycle of input A.C. ✔

Option A: is located on the emitter

Option B: is located on the base

Option C: is locate on the collector

Option D: points form north to south

Correct Answer: is located on the emitter ✔

Option A: antimony

Option B: phosphorus

Option C: aluminium

Option D: arsenic

Correct Answer: aluminium ✔

Option A: minority carriers

Option B: majority carriers

Option C: holes

Option D: electron

Correct Answer: majority carriers ✔

Option A: 105 ohm metre

Option B: 106 ohm metre

Option C: 107 ohm metre

Option D: 108 ohm metre

Correct Answer: 108 ohm metre ✔

Option A: Conduction band

Option B: Fermi band

Option C: Valence band

Option D: Forbidden band

Correct Answer: Conduction band ✔

Option A: during the manufacturing process

Option B: under forward bias

Option C: under reverse bias

Option D: when temperature varies

Correct Answer: during the manufacturing process ✔

Option A: using a transistor

Option B: suppressing the harmonics in A.C voltage

Option C: suppressing half wave of A.C supply by using diode

Option D: using a Coolidge tube

Correct Answer: suppressing half wave of A.C supply by using diode ✔

Option A: equal to emitter current

Option B: slightly less than emitter current

Option C: greater than emitter current

Option D: any of above

Correct Answer: slightly less than emitter current ✔

Option A: n

Option B: p

Option C: mix

Option D: any of above

Correct Answer: n ✔

Option A: The switch

Option B: The light emitting diode

Option C: The photo diodes

Option D: Solar cells.

Correct Answer: The light emitting diode ✔

Option A: An amplifier.

Option B: A rectifier

Option C: Filtering circuit

Option D: Converter.

Correct Answer: A rectifier ✔

Option A: It has low resistance to the current flow when forward biased & high resistance when reverse biased.

Option B: It has low resistance to the current flow when forward biased.

Option C: It has high resistance to the current flow when reverse biased

Option D: Its conductivity increases with rise of temperature.

Correct Answer: It has low resistance to the current flow when forward biased & high resistance when reverse biased. ✔

Option A: is located on the emitter

Option B: is located on the base

Option C: is locate on the collector

Option D: points form north to south

Correct Answer: is located on the emitter ✔

Option A: protons

Option B: positrons

Option C: electrons

Option D: photons

Correct Answer: electrons ✔

Option A: insulator

Option B: conductor

Option C: semi conductor

Option D: any of above

Correct Answer: insulator ✔

Option A: constant

Option B: zero

Option C: changing

Option D: infinite

Correct Answer: changing ✔

Option A: holes in n-type and free electrons in p-type

Option B: holes in n-type and p-type

Option C: free electrons in n-type and holes in p-type

Option D: free electrons in n-type and p-type

Correct Answer: holes in n-type and free electrons in p-type ✔

Option A: collector

Option B: emitter

Option C: base

Option D: any of above

Correct Answer: base ✔

Option A: capacitor

Option B: inductor

Option C: on switch

Option D: off switch

Correct Answer: off switch ✔

Option A: pentavalent

Option B: trivalent

Option C: divalent

Option D: tetravalent

Correct Answer: tetravalent ✔

Option A: majority carriers

Option B: minority carriers

Option C: dual carriers

Option D: blockers

Correct Answer: minority carriers ✔

Option A: Less than ordinary light

Option B: More than ordinary light

Option C: Equal to ordinary light

Option D: Different for different colours or frequency

Correct Answer: Equal to ordinary light ✔

Option A: Further stimulation

Option B: Lasing more

Option C: For producing more energetic lasers

Option D: All

Correct Answer: Further stimulation ✔

Option A: Ne only

Option B: He-Ne both

Option C: Electrons of He

Option D: Electrons Ne

Correct Answer: Ne only ✔

Option A: 10-4 sec

Option B: 10-5 sec

Option C: 10-3 sec

Option D: 10-8 sec

Correct Answer: 10-3 sec ✔

Option A: Metal stable state

Option B: Normal state

Option C: Inverted population

Option D: All the above

Correct Answer: Inverted population ✔

Option A: Stimulated

Option B: Absorbed

Option C: Cause X-ray emission

Option D: Cause laser production

Correct Answer: Absorbed ✔

Option A: It does emit radiation

Option B: Its size as compare to proton and neutron is very small

Option C: No antiparticle of electron is present

Option D: The velocity of electron must be very high according to uncertainty principle

Correct Answer: The velocity of electron must be very high according to uncertainty principle ✔

Option A: Line spectrum of atoms

Option B: Production of x-rays.

Option C: Diffraction by crystalline solids

Option D: Photoelectric effect

Correct Answer: Diffraction by crystalline solids ✔

Option A: Heating the filament

Option B: Electron excitation in the gas

Option C: Ionization of atoms

Option D: All the above

Correct Answer: Electron excitation in the gas ✔

Option A: The ions in a crystal are well arranged

Option B: The lines in a diffraction grating cannot reflect X-rays.

Option C: The penetration power of X-rays is high in a diffraction grating

Option D: The wavelengths of X-rays are of the same order of magnitude as the separation between atoms in a crystal

Correct Answer: The wavelengths of X-rays are of the same order of magnitude as the separation between atoms in a crystal ✔

Option A: Number of incident electron i.e. filament current

Option B: The kinetic energy of the incident electron i.e. the potential difference through which they are accelerated

Option C: The soft target which can easily emit electrons

Option D: All of above are correct

Correct Answer: The kinetic energy of the incident electron i.e. the potential difference through which they are accelerated ✔

Option A: 6.2 x 10-10m

Option B: 9.1 x 10-18m

Option C: 3.11 x 10-10m

Option D: 4 x 10-10m

Correct Answer: 6.2 x 10-10m ✔

Option A: The illumination of the target metal by ultra-violet radiation

Option B: The bombardment of the target by protons

Option C: The bombardment of target by electrons

Option D: The absorption of radiation by the target metal

Correct Answer: The bombardment of target by electrons ✔

Option A: Reducing the pressure or cooling the target

Option B: Increasing the temperature of the filament.

Option C: Using a target element of higher atomic number

Option D: Increasing the potential difference between the cathode and the target

Correct Answer: Increasing the potential difference between the cathode and the target ✔

Option A: B-rays

Option B: X-rays

Option C: Far infrared

Option D: Infrared

Correct Answer: X-rays ✔

Option A: he/ev

Option B: he/Vc

Option C: eV/h

Option D: impossible to predict

Correct Answer: he/ev ✔

Option A: A & B

Option B: B & C

Option C: A & C

Option D: A B & C

Correct Answer: B & C ✔

Option A: increases

Option B: it decreases

Option C: it remains same

Option D: sometimes increases and sometimes decreases

Correct Answer: it remains same ✔

Option A: Cathode rays

Option B: Positive rays

Option C: γ-rays

Option D: Beta rays

Correct Answer: γ-rays ✔

Option A: γ-rays

Option B: Infra red radiation

Option C: Visible light

Option D: Ultraviolet rays

Correct Answer: γ-rays ✔

Option A: ultraviolet rays

Option B: X-rays

Option C: infra red radiation

Option D: visible radiation

Correct Answer: infra red radiation ✔

Option A: pair production

Option B: Compton effect

Option C: annihilation of matter

Option D: X-rays production

Correct Answer: X-rays production ✔

Option A: applied voltage

Option B: frequency

Option C: source

Option D: all of the above

Correct Answer: frequency ✔

Option A: 4th orbit

Option B: 5th orbit

Option C: 3rd orbit

Option D: 2nd orbit

Correct Answer: 4th orbit ✔

Option A: Ke2/rn

Option B: Ke2/rn2

Option C: ÀKe2/rn

Option D: ÀKe2/rn2

Correct Answer: Ke2/rn ✔

Option A: 13.60 eV

Option B: 3.40 eV

Option C: 0.85 eV

Option D: 1.51 eV

Correct Answer: 0.85 eV ✔

Option A: continuous spectra for atoms

Option B: discrete spectra for atoms

Option C: either continuous nor discrete

Option D: no spectrum

Correct Answer: continuous spectra for atoms ✔

Option A: radiate electromagnetic energy with a continuous distribution of wavelength

Option B: absorb particular wavelengths when white light is incident on them

Option C: radiate electromagnetic energy of discrete characteristic wavelength

Option D: emit either invisible or visible light

Correct Answer: radiate electromagnetic energy of discrete characteristic wavelength ✔

Option A: photo electric effect

Option B: ionization

Option C: shadow photograph

Option D: any of above

Correct Answer: shadow photograph ✔

Option A: 1st to 5th orbit

Option B: 2nd to 5th orbit

Option C: 3rd to 5th orbit

Option D: 4th to 5th orbit

Correct Answer: 1st to 5th orbit ✔

Option A: band spectrum

Option B: line spectrum

Option C: continuous spectrum

Option D: absorption spectrum

Correct Answer: line spectrum ✔

Option A: three

Option B: four

Option C: five

Option D: six

Correct Answer: five ✔

Option A: of unknown nature

Option B: high energy electrons

Option C: high energy photons

Option D: radio isotopes

Correct Answer: high energy photons ✔

Option A: its energy levels are too close to each other

Option B: its energy levels are too far apart

Option C: it is too small in size

Option D: it has a single electron

Correct Answer: it has a single electron ✔

Option A: 10-10s

Option B: 10-8s

Option C: 10-6s

Option D: 10-9s

Correct Answer: 10-8s ✔

Option A: Balmer series

Option B: Pfund series

Option C: Bracket series

Option D: Lymann series

Correct Answer: Lymann series ✔

Option A: 18.336

Option B: 1836

Option C: 18360

Option D: 183.6

Correct Answer: 1836 ✔

Option A: spectrometer

Option B: galvanometer

Option C: interferometer

Option D: none of these

Correct Answer: spectrometer ✔

Option A: Newton

Option B: Einstein

Option C: Raleigh

Option D: Planks

Correct Answer: Raleigh ✔

Option A: object is beyond C

Option B: if the object is with in C

Option C: if the object is within f

Option D: both B and C

Correct Answer: both B and C ✔

Option A: C = 4fd

Option B: C = 8fd

Option C: C = 16fd

Option D: C = 5/2fd

Correct Answer: C = 16fd ✔

Option A: 300km

Option B: 200km

Option C: 100km

Option D: 20km

Correct Answer: 100km ✔

Option A: to produce parallel beams of light

Option B: to filter the light rays

Option C: to make them

Option D: no function

Correct Answer: to produce parallel beams of light ✔

Option A: Multimode index fiber

Option B: Graded index fiber

Option C: Single mode step index fiber

Option D: Copper wire

Correct Answer: Graded index fiber ✔

Option A: fo+fe

Option B: fo/fe

Option C: fe/fo

Option D: (1+fo/fe)L/fo

Correct Answer: fo/fe ✔

Option A: Diodes

Option B: Repeaters

Option C: Laser

Option D: Transformer

Correct Answer: Repeaters ✔

Option A: 42°

Option B: 47°

Option C: 52°

Option D: 50°

Correct Answer: 42° ✔

Option A: center of curvature

Option B: focus

Option C: optical center

Option D: aperture

Correct Answer: focus ✔

Option A: 10 dioptre

Option B: 10 dioptre

Option C: 1 / 10 dioptre

Option D: 1 / 10 dioptre

Correct Answer: 10 dioptre ✔

Option A: 2 f

Option B: 2.5 f

Option C: 3f

Option D: 4f

Correct Answer: 4f ✔

Option A: between principal focus and center of curvature

Option B: beyond 2 f

Option C: at the principal focus

Option D: between principal focus and optical center

Correct Answer: between principal focus and optical center ✔

Option A: 0.5

Option B: 0.2

Option C: 1

Option D: 2

Correct Answer: 2 ✔

Option A: increases with increase in age

Option B: decreases with increase in age

Option C: neither increases nor decreases

Option D: becomes infinite after 60 years

Correct Answer: increases with increase in age ✔

Option A: zero

Option B: focus

Option C: 2 f

Option D: f/2

Correct Answer: f/2 ✔

Option A: fo + fe

Option B: fo – fe

Option C: fo / fe

Option D: fe / fo

Correct Answer: fo + fe ✔

Option A: real and inverted

Option B: real and erect

Option C: virtual and erect

Option D: virtual and inverted

Correct Answer: virtual and inverted ✔

Option A: same

Option B: different

Option C: zero

Option D: different with refractive index of core higher than cladding

Correct Answer: different ✔

Option A: f2 + f1

Option B: f2 – f1

Option C: f1f2/f2+f1

Option D: f1f2/f1-f2

Correct Answer: f1f2/f1-f2 ✔

Option A: chromatic aberration

Option B: spherical aberration

Option C: both spherical and chromatic

Option D: distortion

Correct Answer: spherical aberration ✔

Option A: 15 cm

Option B: 25 cm

Option C: 30 cm

Option D: 40 cm

Correct Answer: 25 cm ✔

Option A: increase with increase in focal length

Option B: increase with decrease in focal length

Option C: no effect with decrease or increase with focal length

Option D: list distance of distinct vision

Correct Answer: increase with decrease in focal length ✔

Option A: real and erect

Option B: virtual and erect

Option C: real and inverted

Option D: virtual

Correct Answer: real and inverted ✔

Option A: real

Option B: virtual

Option C: positive

Option D: negative

Correct Answer: negative ✔

Option A: meter

Option B: watt

Option C: diopter

Option D: horsepower

Correct Answer: diopter ✔

Option A: focal length

Option B: principal axis

Option C: aperture

Option D: radius of curvature

Correct Answer: principal axis ✔