2A + B → A2B, ( – rA) = k.CA.CB
A. A + B ⇌ AB; AB + A → A2B
B. A + B → AB; AB + A → A2B
C. A + A → AA; AA + B → A2B
D. A + A ⇌ AA; AA + B → A2B
Correct Answer: A + A ⇌ AA; AA + B → A2B ✔
Last Updated: February 20, 2019
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