A. XA = k . t
B. [CA0/(1 + εA XA)] (dXA/dt) = k
C. -ln(1 – XA) = kt
D. εA . ln (1 – XA) = k . t
Correct Answer: [CA0/(1 + εA XA)] (dXA/dt) = k ✔
Last Updated: February 20, 2019
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