A tank is filled in eight hours by three pipes A, B and C. Pipe A is twice as fast as pipe B, and B is twice as fast as C. How much time will pipe B alone take to fill the tank?

A. 24 hours
B. 28 hours
C. 32 hours
D. 36 hours

Explanation:

1/A + 1/B + 1/C = 1/8 (Given)

Also given that A = 2B and B = 2C
=> 1/2B + 1/B + 2/B = 1/8
=> (1 + 2 + 4)/2B = 1/8
=> 2B/7 = 8
=> B = 28 hours.

Correct Answer: 28 hours ✔

Last Updated: February 08, 2020