Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case?

Question

Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case?

Answer 1

A. 1020
B. 1026
C. 1030
D. 1022

Explanation:

Lowest 4-digit number is 1000.
LCM of 3, 4 and 5 is 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 – 40) = 1020.
Now, add the remainder 2 that’s required. Thus, the answer is 1022.

Correct Answer: 1022 ✔

Last Updated: February 07, 2020