In a school, 40 % of the students play football and 50 % play cricket. If 18 % of the students play neither football nor cricket, the percentage of students playing both is________?

A. 40 %
B. 32 %
C. 22 %
D. 8 %

Explanation:

Let A = set of students who play football and

B = set of students play cricket.

Then n(A) = 40, n (B) = 50 and

n(A U B) = (100 – 18) = 82

n(A U B) = n(A) + n(B) – n(A ∩ B)

n(A∩B) = n(A) + n(B) – n(AUB) = (40 + 50 -82) = 8

Percentage of the students who play both = 8%

Correct Answer: 8 % ✔

Last Updated: February 07, 2020