The number of sequences in which 7 players can throw a ball, so that the youngest player may not be the last is -.

A. 4000
B. 2160
C. 4320
D. 5300

Explanation:

x Not younger_______ ↑

The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.
The required number of ways = 6(6!) = 4320

Correct Answer: 4320 ✔

Last Updated: February 07, 2020