A body is falling freely under gravity. How much distance it falls during an interval of time between 1st and 2nd seconds of its motion, taking g=10 ?

A. 15 m
B. 20 m
C. 5 m
D. 25 m

answer is 15 m
S=ut+1/2gt^2
u=0 ,g = 10ms-2
During ist time interval
S1=0+1/2(10)(1)^2
S1=5m
During 2nd time interval
S2=0+1/2(10)(2)^2
S2=20m
Distance covered by body during an interval of time between first and second seconds of its motion = (S2 – S1 ) = 20–5 = 15m .

Correct Answer: 15 m ✔

Last Updated: May 16, 2023