Option A: at which crystals first start forming from molten metal when it is cooled
Option B: at which new spherical crystals first begin to form from the old deformed one when a strained metal is heated
Option C: at which change of allotropic form takes place
Option D: at which crystals grow bigger in size
Correct Answer: at which new spherical crystals first begin to form from the old deformed one when a strained metal is heated ✔
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Option A: room temperature
Option B: above melting point
Option C: between 1400°C and 1539°C
Option D: between 910°C and 1400°C
Correct Answer: between 1400°C and 1539°C ✔
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Option A: below 10°K
Option B: above 100°K
Option C: around 0°C
Option D: around 100°C
Correct Answer: below 10°K ✔
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Option A: alpha iron, beta iron and gamma iron
Option B: alpha iron and beta iron
Option C: body centred cubic a-iron and face centred cubic a-iron
Option D: alpha iron, gamma from and delta iron
Correct Answer: alpha iron, gamma from and delta iron ✔
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Option A: room temperature
Option B: near melting point
Option C: between 1400°C and 1539°C
Option D: between 910°C and 1400°C
Correct Answer: between 910°C and 1400°C ✔
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Option A: ferrite
Option B: pearlite
Option C: anstenite
Option D: ferrite and cementite
Correct Answer: ferrite ✔
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Option A: 0.2%
Option B: 0.8%
Option C: 1.3%
Option D: 2%
Correct Answer: 2% ✔
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Option A: in a random manner
Option B: in a haphazard way
Option C: in circular motion
Option D: back and forth like tiny pendulums
Correct Answer: back and forth like tiny pendulums ✔
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Option A: 770°C
Option B: 910°C
Option C: 1440°C
Option D: 1539°C
Correct Answer: 910°C ✔
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Option A: body centred cubic
Option B: face centred cubic
Option C: hexagonal close packed
Option D: cubic structure
Correct Answer: face centred cubic ✔
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Option A: body centred cubic
Option B: face centred cubic
Option C: hexagonal close packed
Option D: cubic structure
Correct Answer: body centred cubic ✔
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Option A: 0.1 to 1.2%
Option B: 1.5 to 2.5%
Option C: 2.5 to 4%
Option D: 4 to 4.5%
Correct Answer: 4 to 4.5% ✔
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Option A: raw material for blast furnace
Option B: product of blast furnace made by reduction of iron ore
Option C: iron containing huge quantities of carbon
Option D: iron in molten form in the ladles
Correct Answer: product of blast furnace made by reduction of iron ore ✔
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Option A: cementite
Option B: free carbon
Option C: flakes
Option D: spheroids
Correct Answer: spheroids ✔
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Option A: hard
Option B: high in strength
Option C: highly resistant to corrosion
Option D: heat treated to change its properties
Correct Answer: highly resistant to corrosion ✔
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Option A: It contains carbon of the order of 0 to 0.25%
Option B: It melts at 1535°C
Option C: It is very soft and ductile
Option D: It can be easily forge welded
Correct Answer: It is made by adding suitable percent¬age of carbon to molten iron and subjecting the product to repeated hammering and rolling ✔
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Option A: allotropic change
Option B: recrystallisation
Option C: heat treatment
Option D: precipitation
Correct Answer: allotropic change ✔
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Option A: high tensile strength
Option B: its elastic limit close to the ultimate breaking strength
Option C: high ductility
Option D: all of the above
Correct Answer: its elastic limit close to the ultimate breaking strength ✔
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Option A: free form
Option B: combined form
Option C: nodular form
Option D: flat form
Correct Answer: partly in free and partly in combined state ✔
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An important property of malleable cast iron in comparison to grey cast iron is the high__________?
Option A: compressive strength
Option B: ductility
Option C: carbon content
Option D: hardness
Correct Answer: ductility ✔
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Option A: made by adding carbon in steel
Option B: refined from cast iron
Option C: an alloy of iron and carbon with varying quantities of phosphorus and sulphur
Option D: extensively used for making cutting tools
Correct Answer: an alloy of iron and carbon with varying quantities of phosphorus and sulphur ✔
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Option A: which are destroyed by burning
Option B: which after their destruction are recycled to produce fresh steel
Option C: which are deoxidised in the ladle with silicon and aluminium
Option D: in which carbon is completely burnt
Correct Answer: which are deoxidised in the ladle with silicon and aluminium ✔
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Option A: carbon
Option B: vanadium
Option C: manganese
Option D: cobalt
Correct Answer: vanadium ✔
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Option A: 0.025%
Option B: 0.06%
Option C: 0.1%
Option D: 0.25%
Correct Answer: 0.025% ✔
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Option A: chromium and nickel
Option B: sulphur, phosphorus, lead
Option C: vanadium, aluminium
Option D: tungsten, molybdenum, vanadium, chromium
Correct Answer: chromium and nickel ✔
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Option A: mild steel
Option B: alloy steel
Option C: high carbon
Option D: tungsten steel
Correct Answer: high carbon ✔
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Option A: providing corrosion resistance
Option B: improving machining properties
Option C: providing high strength at elevated temperatures
Option D: raising the elastic limit
Correct Answer: improving machining properties ✔
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Option A: 0.02%
Option B: 0.3%
Option C: 0.63%
Option D: 0.8%
Correct Answer: 0.8% ✔
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Option A: nickel, copper
Option B: nickel, molybdenum
Option C: zinc, tin, lead
Option D: nickel, lead and tin
Correct Answer: nickel, copper ✔
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Option A: silver metal
Option B: duralumin
Option C: Hastelloy
Option D: monel metal
Correct Answer: invar ✔
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Option A: cast iron
Option B: forged steel
Option C: mild steel
Option D: high carbon steel
Correct Answer: high carbon steel ✔
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Option A: ductile
Option B: malleable
Option C: homogeneous
Option D: isotropic
Correct Answer: isotropic ✔
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Option A: dipping steel in cyanide bath
Option B: reacting steel surface with cyanide salts
Option C: adding carbon and nitrogen by heat treatment of steel to increase its surface hardness
Option D: obtaining cyanide salts
Correct Answer: adding carbon and nitrogen by heat treatment of steel to increase its surface hardness ✔
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Option A: hysteresis
Option B: creep
Option C: visco elasticity
Option D: Boeschinger effect
Correct Answer: Boeschinger effect ✔
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Option A: 600 VPN
Option B: 1500 VPN
Option C: 1000 to 1100 VPN
Option D: 250 VPN
Correct Answer: 1000 to 1100 VPN ✔
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Option A: cast iron
Option B: mild steel
Option C: non-ferrous materials
Option D: wrought iron
Correct Answer: stainless steel ✔
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Option A: RC 65
Option B: RC 48
Option C: RC 57
Option D: RC 80
Correct Answer: RC 48 ✔
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Option A: substitutional solid solution
Option B: interstitial solid solution
Option C: intermetallic compounds
Option D: all of the above
Correct Answer: substitutional solid solution ✔
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Option A: aluminium
Option B: tin
Option C: zinc
Option D: lead
Correct Answer: silver ✔
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Option A: refine grain structure
Option B: reduce segregation in casting
Option C: improve mechanical properties
Option D: induce stresses-
Correct Answer: induce stresses- ✔
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Option A: in which atoms align themselves in a geometric pattern upon solidification
Option B: in which there is no definite atomic structure and atoms exist in a random pattern just as in a liquid
Option C: which is not attacked by phosphorous
Option D: which emits fumes on melting
Correct Answer: in which there is no definite atomic structure and atoms exist in a random pattern just as in a liquid ✔
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Option A: zinc
Option B: lead
Option C: silver
Option D: glass
Correct Answer: glass ✔
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Option A: electroplating
Option B: cyaniding
Option C: induction hardening
Option D: nitriding
Correct Answer: electroplating ✔
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Option A: improves wear resistance, cutting ability and toughness
Option B: refines grain size and produces less tendency to carburisation, improves corrosion and heat resistant properties
Option C: improves cutting ability and reduces hardenability
Option D: gives ductility, toughness, tensile strength and anticorrosion properties
Correct Answer: improves wear resistance, cutting ability and toughness ✔
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Option A: brass
Option B: cast iron
Option C: aluminium
Option D: steel
Correct Answer: steel ✔
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Option A: cobalt
Option B: nickel
Option C: vanadium
Option D: iron
Correct Answer: cobalt ✔
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Option A: improve machinability
Option B: improve ductility
Option C: improve toughness
Option D: release stresses
Correct Answer: improve machinability ✔
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Option A: promotes decarburisation
Option B: provides high hot hardness
Option C: forms very hard carbides and thus in-creases wear resistance
Option D: promotes retention of austenite
Correct Answer: forms very hard carbides and thus in-creases wear resistance ✔
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Option A: RC 65
Option B: RC 48
Option C: RC 57
Option D: RC 80
Correct Answer: RC 57 ✔
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Option A: relieve stresses
Option B: harden steel slightly
Option C: improve machining characteristic
Option D: soften material
Correct Answer: harden steel slightly ✔
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Option A: substitutional solution
Option B: interstitial solid solution
Option C: intermetallic compounds
Option D: all of the above
Correct Answer: interstitial solid solution ✔
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Option A: hot working
Option B: tempering
Option C: normalising
Option D: annealing
Correct Answer: annealing ✔
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Option A: RC 65
Option B: RC 48
Option C: RC 57
Option D: RC 80
Correct Answer: RC 65 ✔
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Option A: formation of bainite structure
Option B: carburised structure
Option C: martenistic structure
Option D: lamellar layers of carbide distributed throughout the structure
Correct Answer: formation of bainite structure ✔
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Option A: hardening surface of workpiece to ob-tain hard and wear resistant surface
Option B: heating and cooling rapidly
Option C: increasing hardness throughout
Option D: inducing hardness by continuous process
Correct Answer: hardening surface of workpiece to ob-tain hard and wear resistant surface ✔
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Option A: tin, antimony, copper
Option B: tin and copper
Option C: tin and lead
Option D: lead and zinc
Correct Answer: tin and copper ✔
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Option A: nickel, chromium and iron
Option B: nickel, copper
Option C: nickel, chromium
Option D: nickel, zinc
Correct Answer: nickel, chromium and iron ✔
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Option A: mild steel
Option B: cast iron
Option C: H.S.S.
Option D: high carbon
Correct Answer: high carbon ✔
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Option A: silver and some impurities
Option B: refined silver
Option C: nickel, copper and zinc
Option D: nickel and copper
Correct Answer: nickel, copper and zinc ✔
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Option A: aluminium, copper etc
Option B: nickel, molybdenum etc
Option C: nickel, copper, etc
Option D: all of the above
Correct Answer: nickel, molybdenum etc ✔
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Option A: sulphur, lead, phosphorous
Option B: silicon, aluminium, titanium
Option C: vanadium, aluminium
Option D: chromium, nickel
Correct Answer: sulphur, lead, phosphorous ✔
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Option A: nickel
Option B: chromium
Option C: tungsten
Option D: vanadium
Correct Answer: chromium ✔
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Option A: flywheel of steam engine
Option B: cast iron pipes”
Option C: cycle chains
Option D: gas turbine blades
Correct Answer: gas turbine blades ✔
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Option A: 0.025%
Option B: 0.26%
Option C: 0.8%
Option D: 1.25%
Correct Answer: 1.7%. ✔
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Option A: amount of carbon it contains
Option B: the shape and distribution of the car-bides in iron
Option C: method of fabrication
Option D: contents of alloying elements
Correct Answer: the shape and distribution of the car-bides in iron ✔
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Option A: malleable iron
Option B: nodular iron
Option C: spheroidal iron
Option D: grey iron
Correct Answer: malleable iron ✔
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Option A: 80% or more iron
Option B: 50% or more iron
Option C: alloying elements like chromium, tungsten nickel and copper
Option D: elements like phosphorus, sulphur and silicon in varying quantities
Correct Answer: 50% or more iron ✔
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Option A: tenacity
Option B: brittleness
Option C: plasticity
Option D: corrosion resistance
Correct Answer: hardness ✔
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Option A: free carbon
Option B: graphite
Option C: cementite
Option D: white carbon
Correct Answer: cementite ✔
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Option A: no graphite
Option B: a very high percentage of graphite
Option C: a low percentage of graphite
Option D: graphite as its basic constituent of composition
Correct Answer: no graphite ✔
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Option A: paramagnetic
Option B: ferromagnetic
Option C: ferroelectric
Option D: dielectric
Correct Answer: ferromagnetic ✔
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Option A: hard’
Option B: soft
Option C: ductile
Option D: tough
Correct Answer: hard’ ✔
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Option A: face-centred cubic lattice
Option B: body-centred cubic lattice
Option C: hexagonal close-packed lattice
Option D: all of the above
Correct Answer: face-centred cubic lattice ✔
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Option A: cementite
Option B: free carbon
Option C: flakes
Option D: spheroids
Correct Answer: nodular aggregates of graphite ✔
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Option A: cementite
Option B: free carbon
Option C: flakes
Option D: spheroids
Correct Answer: flakes ✔
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Option A: malleability
Option B: ductility
Option C: surface finish
Option D: damping characteristics
Correct Answer: damping characteristics ✔
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Option A: 0.5 to 1%
Option B: 1 – 2%
Option C: 2.5 to 4.5%
Option D: 5 – 7%
Correct Answer: 2.5 to 4.5% ✔
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Option A: the points where no further change oc-curs
Option B: constant for all metals
Option C: the points where there is no further flow of metal
Option D: the points of discontinuity
Correct Answer: the points of discontinuity ✔
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Option A: body centred cubic
Option B: face centred cubic
Option C: hexagonal close packed
Option D: cubic structure
Correct Answer: body centred cubic ✔
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Option A: molecular change
Option B: physical change
Option C: allotropic change
Option D: solidus change
Correct Answer: allotropic change ✔
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Option A: below 723°C
Option B: 770 – 910°C
Option C: 910-1440°C
Option D: 1400-1539°C
Correct Answer: below 723°C ✔
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Option A: 770°C
Option B: 910°C
Option C: 1050°C
Option D: below recrystallisation temperature
Correct Answer: 770°C ✔
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Option A: austenite
Option B: pearlite
Option C: ferrite
Option D: cementlte
Correct Answer: ferrite ✔
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Option A: has a fixed structure under all conditions
Option B: exists in several crystal forms at different temperatures
Option C: responds to heat treatment
Option D: has its atoms distributed in a random pattern
Correct Answer: exists in several crystal forms at different temperatures ✔
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Option A: stages at which allotropic forms change
Option B: stages at which further heating does not increase temperature for some time
Option C: stages at which properties do not change with increase in temperature
Option D: there is nothing like points of arrest
Correct Answer: stages at which allotropic forms change ✔
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Option A: increase
Option B: decrease
Option C: remain same
Option D: first increase and then decrease
Correct Answer: increase ✔
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Option A: creep
Option B: hot tempering
Option C: hot hardness
Option D: fatigue
Correct Answer: hot hardness ✔
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Option A: elastic properties in all directions
Option B: stresses induced in all directions
Option C: thermal properties in all directions
Option D: electric and magnetic properties in all directions
Correct Answer: elastic properties in all directions ✔
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Option A: in which parts are not loaded
Option B: in which stress remains constant on in-creasing load
Option C: in which deformation tends to loosen the joint and produces a stress reduced
Option D: stress reduces on increasing load
Correct Answer: in which deformation tends to loosen the joint and produces a stress reduced ✔
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Option A: low carbon steel
Option B: medium carbon steel
Option C: high carbon steel
Option D: alloy steel
Correct Answer: low carbon steel ✔
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Option A: ability to undergo large permanent deformations in compression
Option B: ability to recover its original form
Option C: ability to undergo large permanent deformations in tension
Option D: all of the above
Correct Answer: ability to undergo large permanent deformations in compression ✔
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