**Option A:** the tangent of the angle of friction is equal to coefficient of friction

**Option B:** the angle of repose is equal to angle of friction

**Option C:** the tangent of the angle of repose is equal to coefficient of friction

**Option D:** the sine of the angle of repose is equal to coefficient to friction

**Correct Answer: **the sine of the angle of repose is equal to coefficient to friction ✔

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**Option A:** The C.G. of a circle is at its center

**Option B:** The C.G. of a triangle is at the intersection of its medians

**Option C:** The C.G. of a rectangle is at the inter-section of its diagonals

**Option D:** The C.G. of a semicircle is at a distance of r/2 from the center

**Correct Answer: **The C.G. of a semicircle is at a distance of r/2 from the center ✔

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**Option A:** balance each other

**Option B:** produce a couple and an unbalanced force

**Option C:** are equivalent

**Option D:** produce a moment of couple

**Correct Answer: **balance each other ✔

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**Option A:** post friction

**Option B:** limiting friction

**Option C:** kinematic friction

**Option D:** frictional resistance

**Correct Answer: **dynamic friction ✔

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**Option A:** towards the wall at its upper end

**Option B:** away from the wall at its upper end

**Option C:** upwards at its upper end

**Option D:** downwards at its upper end

**Correct Answer: **upwards at its upper end ✔

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**Option A:** coefficient of friction

**Option B:** angle of friction

**Option C:** angle of repose

**Option D:** sliding friction

**Correct Answer: **coefficient of friction ✔

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**Option A:** 2n-3

**Option B:** n-l

**Option C:** ‘2n-l

**Option D:** n – 2

**Correct Answer: **2n-3 ✔

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**Option A:** two members with unknown forces of the frame

**Option B:** three members with unknown forces of the frame

**Option C:** four members with unknown forces of the frame

**Option D:** three members with known forces of the frame

**Correct Answer: **three members with unknown forces of the frame ✔

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**Option A:** concurrence of the medians

**Option B:** intersection of its altitudes

**Option C:** intersection of bisector of angles

**Option D:** intersection of diagonals

**Correct Answer: **concurrence of the medians ✔

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**Option A:** compression or tension

**Option B:** buckling or shear

**Option C:** shear or tension

**Option D:** all of the above

**Correct Answer: **compression or tension ✔

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**Option A:** angle between normal reaction and the resultant of normal reaction and the limiting friction

**Option B:** ratio of limiting friction and normal reaction

**Option C:** the ratio of minimum friction force to the friction force acting when the body is just about to move

**Option D:** the ratio of minimum friction force to friction force acting when the body is in motion

**Correct Answer: **angle between normal reaction and the resultant of normal reaction and the limiting friction ✔

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**Option A:** maximum

**Option B:** minimum

**Option C:** zero

**Option D:** infinity

**Correct Answer: **zero ✔

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**Option A:** area of contact

**Option B:** shape of surfaces

**Option C:** strength of surfaces

**Option D:** nature of surface

**Correct Answer: **nature of surface ✔

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**Option A:** 20 kg, – ve sense

**Option B:** 20 kg, + ve sense

**Option C:** 10 kg, + ve sense

**Option D:** 10 kg, – ve sense

**Correct Answer: **20 kg, – ve sense ✔

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**Option A:** along the plane

**Option B:** horizontally

**Option C:** vertically

**Option D:** at an angle equal to the angle of friction to the inclined plane

**Correct Answer: **at an angle equal to the angle of friction to the inclined plane ✔

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**Option A:** reaction of any smooth surface with which the body is in contact

**Option B:** reaction of a rough surface of a body which rolls on it without slipping

**Option C:** reaction at a point or an axis, fixed in space, around which a body is con-strained to turn

**Option D:** all of the above

**Correct Answer: **all of the above ✔

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**Option A:** 2.5 cm

**Option B:** 3.0 cm

**Option C:** 4.0 cm

**Option D:** 5.0 cm

**Correct Answer: **4.0 cm ✔

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**Option A:** r/2

**Option B:** 2r/3

**Option C:** r/A

**Option D:** 3r/2

**Correct Answer: **r/2 ✔

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**Option A:** 0.5 cm

**Option B:** 1.0 cm

**Option C:** 1.5 cm

**Option D:** 2.5 cm

**Correct Answer: **0.5 cm ✔

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**Option A:** catenary

**Option B:** parabola

**Option C:** hyperbola

**Option D:** elliptical

**Correct Answer: **parabola ✔

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**Option A:** kg m2

**Option B:** m4

**Option C:** kg/m2

**Option D:** kg/m

**Correct Answer: **kg m2 ✔

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**Option A:** one-fourth of the total height above base

**Option B:** one-third of the total height above base

**Option C:** one-half of the total height above base

**Option D:** three-eighth of the total height above the base

**Correct Answer: **one-third of the total height above base ✔

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## The center of percussion of the homogeneous rod of length L suspended at the top will be__________?

**Option A:** L/2

**Option B:** L/3

**Option C:** 3L/4

**Option D:** 2L/3

**Correct Answer: **L/3 ✔

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**Option A:** one-fourth of the total height above base

**Option B:** one-third of the total height above base

**Option C:** one-half of the total height above base

**Option D:** three-eighth of the total height above the base

**Correct Answer: **one-fourth of the total height above base ✔

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**Option A:** kg m2

**Option B:** m4

**Option C:** kg/m2

**Option D:** m3

**Correct Answer: **m4 ✔

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**Option A:** the point of C.G.

**Option B:** the point of metacentre

**Option C:** the point of application of the resultant of all the forces tending to cause a body to rotate about a certain axis

**Option D:** point of suspension

**Correct Answer: **the point of application of the resultant of all the forces tending to cause a body to rotate about a certain axis ✔

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**Option A:** the center of heavy portion

**Option B:** the bottom surface

**Option C:** the mid point of its axis

**Option D:** all of the above

**Correct Answer: **the mid point of its axis ✔

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**Option A:** resultant couple

**Option B:** moment of the forces

**Option C:** resulting couple

**Option D:** moment of the couple

**Correct Answer: **moment of the couple ✔

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**Option A:** three forces acting at a point will be in equilibrium

**Option B:** three forces acting at a point can be represented by a triangle, each side being proportional to force

**Option C:** if three forces acting upon a particle are represented in magnitude and

**Option D:** if three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two

**Correct Answer: **if three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two ✔

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**Option A:** reducing the problem of kinetics to equivalent statics problem

**Option B:** determining stresses in the truss

**Option C:** stability of floating bodies

**Option D:** designing safe structures

**Correct Answer: **reducing the problem of kinetics to equivalent statics problem ✔

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**Option A:** three forces acting at a point will be in equilibrium

**Option B:** three forces acting at a point can be represented by a triangle, each side being proportional to force

**Option C:** if three forces acting upon a patticle are represented in magnitude and direction by the sides of a triangle, taken in order, they will be in equilibrium

**Option D:** if three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two

**Correct Answer: **if three forces acting upon a patticle are represented in magnitude and direction by the sides of a triangle, taken in order, they will be in equilibrium ✔

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**Option A:** energy

**Option B:** mass

**Option C:** momentum

**Option D:** angle

**Correct Answer: **momentum ✔

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**Option A:** coplanar non-concurrent forces

**Option B:** non-coplanar concurrent forces

**Option C:** non-coplanar non-concurrent forces

**Option D:** intersecting forces

**Correct Answer: **non-coplanar concurrent forces ✔

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**Option A:** balance each other

**Option B:** constitute a moment

**Option C:** constitute a couple

**Option D:** constitute a moment of couple

**Correct Answer: **constitute a couple ✔

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**Option A:** weight

**Option B:** velocity

**Option C:** acceleration

**Option D:** force

**Correct Answer: **weight ✔

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## A heavy ladder resting on floor and against a vertical wall may not be in equilibrium, if__________?

**Option A:** the floor is smooth, the wall is rough

**Option B:** the floor is rough, the wall is smooth

**Option C:** the floor and wall both are smooth surfaces

**Option D:** the floor and wall both are rough surfaces

**Correct Answer: **the floor and wall both are smooth surfaces ✔

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**Option A:** these forces are equal

**Option B:** the lines of action of these forces meet in a point

**Option C:** the lines of action of these forces are parallel

**Option D:** B. and C. above

**Correct Answer: **D. B. and C. above ✔

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**Option A:** if a system of coplanar forces is in equilibrium, then their algebraic sum is zero

**Option B:** if a system of coplanar forces is in equilibrium, then the algebraic sum of their moments about any point in their plane is zero

**Option C:** the algebraic sum of the moments of any two forces about any point is equal to moment of theiwesultant about the same point

**Option D:** positive and negative couples can be balanced

**Correct Answer: **if a system of coplanar forces is in equilibrium, then the algebraic sum of their moments about any point in their plane is zero ✔

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**Option A:** their total sum is zero

**Option B:** two resolved parts in two directions at right angles are equal

**Option C:** sum of resolved parts in any two per-pendicular directions are both zero

**Option D:** all of them are inclined equally

**Correct Answer: **sum of resolved parts in any two per-pendicular directions are both zero ✔

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**Option A:** maximum when it acts at the center of gravity of a body

**Option B:** different at different points in its line of action

**Option C:** the same at every point in its line of action

**Option D:** minimum when it acts at the C.G. of the body

**Correct Answer: **the same at every point in its line of action ✔

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**Option A:** coplanar force

**Option B:** non-coplanar forces

**Option C:** lever

**Option D:** moment

**Correct Answer: **couple ✔

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**Option A:** centripetal force of earth

**Option B:** gravitational pull exerted by the earth

**Option C:** forces experienced by body in atmosphere

**Option D:** force of attraction experienced by particles

**Correct Answer: **gravitational force of attraction towards the center of the earth ✔

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**Option A:** proportional to normal load between the surfaces

**Option B:** dependent on the materials of contact surface

**Option C:** proportional to velocity of sliding

**Option D:** independent of the area of contact surfaces

**Correct Answer: **proportional to velocity of sliding ✔

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**Option A:** downwards at its upper end

**Option B:** upwards at its upper end

**Option C:** perpendicular to the wall at its upper end

**Option D:** zero at its upper end

**Correct Answer: **zero at its upper end ✔

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**Option A:** angle between normal reaction and the resultant of normal reaction and the limiting friction

**Option B:** ratio of limiting friction and normal reaction

**Option C:** the friction force acting when the body is just about to move

**Option D:** the friction force acting when the body is in motion

**Correct Answer: **ratio of limiting friction and normal reaction ✔

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**Option A:** W

**Option B:** W sin (a + $)

**Option C:** Wtan(a + <|))

**Option D:** W\an(a-)

**Correct Answer: **W ✔

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**Option A:** more inclined when moving

**Option B:** less inclined when moving

**Option C:** more inclined when standing

**Option D:** less inclined when standing

**Correct Answer: **less inclined when standing ✔

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**Option A:** 3t2-lt

**Option B:** 3t2+2t

**Option C:** 6f-8

**Option D:** 6f-4

**Correct Answer: **6f-8 ✔

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**Option A:** bodies having relative motion

**Option B:** two dry surfaces

**Option C:** two lubricated surfaces

**Option D:** solids and liquids

**Correct Answer: **bodies having relative motion ✔

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**Option A:** Wtan(a + )

**Option B:** Wtan(a-)

**Option C:** Wcos(a + )

**Option D:** Wsin(a + )

**Correct Answer: **Wtan(a + ) ✔

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**Option A:** limiting friction

**Option B:** sliding friction

**Option C:** rolling friction

**Option D:** kinematic friction

**Correct Answer: **limiting friction ✔

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**Option A:** balance each other

**Option B:** cannot balance each other

**Option C:** produce moment of a couple

**Option D:** are equivalent

**Correct Answer: **balance each other ✔

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**Option A:** nature of surfaces

**Option B:** area of contact

**Option C:** shape of the surfaces

**Option D:** ail of the above.

**Correct Answer: **nature of surfaces ✔

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**Option A:** j-2

**Option B:** 2j-l

**Option C:** 2/-3

**Option D:** 3/-2

**Correct Answer: **2/-3 ✔

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**Option A:** 38 m

**Option B:** 62.5 m

**Option C:** 96 m

**Option D:** 124 m

**Correct Answer: **62.5 m ✔

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**Option A:** ellipse

**Option B:** hyperbola

**Option C:** parabola

**Option D:** circle

**Correct Answer: **hyperbola ✔

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**Option A:** at distance — from the plane base 3r

**Option B:** at distance — from the plane base 3r

**Option C:** at distance — from the plane base 3r

**Option D:** at distance — from the plane base or

**Correct Answer: **at distance — from the plane base or ✔

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**Option A:** kg m

**Option B:** kcal

**Option C:** wattr

**Option D:** watt hours

**Correct Answer: **wattr ✔

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**Option A:** density of metal can’t be determined

**Option B:** metal is twice as dense as water

**Option C:** metal will float in water

**Option D:** metal is twice as dense as unknown fluid

**Correct Answer: **density of metal can’t be determined ✔

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**Option A:** h/2

**Option B:** J/3

**Option C:** h/6

**Option D:** h/4

**Correct Answer: **h/4 ✔

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**Option A:** right angled triangle

**Option B:** equilateral triangle

**Option C:** square

**Option D:** circle

**Correct Answer: **right angled triangle ✔

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**Option A:** same

**Option B:** double

**Option C:** half

**Option D:** four times

**Correct Answer: **double ✔

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**Option A:** friction

**Option B:** limiting friction

**Option C:** repose

**Option D:** kinematic friction

**Correct Answer: **repose ✔

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**Option A:** mechanical advantage is greater than velocity ratio

**Option B:** mechanical advantage is equal to velocity ratio

**Option C:** mechanical advantage is less than velocity ratio

**Option D:** mechanical advantage is unity

**Correct Answer: **mechanical advantage is equal to velocity ratio ✔

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**Option A:** mechanical advantage is greater than velocity ratio

**Option B:** mechanical advantage is equal to velocity ratio

**Option C:** mechanical advantage is less than velocity ratio

**Option D:** mechanical advantage is unity

**Correct Answer: **mechanical advantage is less than velocity ratio ✔

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**Option A:** straight line

**Option B:** parabola

**Option C:** hyperbola

**Option D:** elliptical

**Correct Answer: **parabola ✔

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**Option A:** coplanar

**Option B:** meet at one point ;

**Option C:** both A. and B. above

**Option D:** all be equal

**Correct Answer: **C. both A. and B. above ✔

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**Option A:** equal to the moment of the couple

**Option B:** constant

**Option C:** both of above are correct

**Option D:** both of above are wrong

**Correct Answer: **equal to the moment of the couple ✔

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**Option A:** remain horizontal

**Option B:** slant up towards direction of pull

**Option C:** slant down towards direction of pull

**Option D:** unpredictable

**Correct Answer: **slant down towards direction of pull ✔

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**Option A:** kinetic friction

**Option B:** limiting friction

**Option C:** angle of repose

**Option D:** coefficient of friction

**Correct Answer: **coefficient of friction ✔

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**Option A:** tangent of angle between normal-reaction and the resultant of normal reaction and limiting friction

**Option B:** ratio of limiting friction and normal reaction

**Option C:** the friction force acting when the body is just about to move

**Option D:** the friction force acting when the body is in motion

**Correct Answer: **the friction force acting when the body is just about to move ✔

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**Option A:** same

**Option B:** more

**Option C:** less

**Option D:** may be less of more depending on nature of surfaces and velocity

**Correct Answer: **less ✔

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**Option A:** one point

**Option B:** one plane

**Option C:** different planes

**Option D:** perpendicular planes

**Correct Answer: **one plane ✔

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**Option A:** kilogram

**Option B:** newton

**Option C:** watt

**Option D:** dyne

**Correct Answer: **newton ✔

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**Option A:** introduce internal stresses

**Option B:** balance the other forces acting on it

**Option C:** retard its motion

**Option D:** change its motion

**Correct Answer: **all of the above ✔

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**Option A:** magnitude

**Option B:** direction

**Option C:** position or line of action

**Option D:** all of the above

**Correct Answer: **all of the above ✔

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**Option A:** magnitude

**Option B:** direction

**Option C:** point of application

**Option D:** all of the above

**Correct Answer: **all of the above ✔

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**Option A:** not a replace them by a single force

**Option B:** to replace them by a single force

**Option C:** to replace them by a single force through C.G.

**Option D:** to replace them by a couple

**Correct Answer: **to replace them by a single force ✔

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**Option A:** if any number of forces acting at a point can be represented by the sides

**Option B:** if any number of forces acting at a point can be represented in direction and magnitude by the sides of a polygon, then the forces are in equilibrium

**Option C:** if a polygon representing forces acting at a point is closed then forces are in equilibrium

**Option D:** if any number of forces acting at a point can be represented in direction and magnitude by the sides of a polygon taken in order, then the forces are in equilibrium

**Correct Answer: **if any number of forces acting at a point can be represented in direction and magnitude by the sides of a polygon taken in order, then the forces are in equilibrium ✔

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**Option A:** one point

**Option B:** two points

**Option C:** plane

**Option D:** perpendicular planes

**Correct Answer: **one point ✔

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**Option A:** newton

**Option B:** pascal

**Option C:** kilogram meter

**Option D:** watt

**Correct Answer: **joule ✔

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**Option A:** kg/cm

**Option B:** ata

**Option C:** atmosphere

**Option D:** mm of wcl

**Correct Answer: **newton ✔

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**Option A:** zeioth order

**Option B:** first order

**Option C:** second order

**Option D:** third order

**Correct Answer: **second order ✔

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**Option A:** non-equilibrium

**Option B:** partial equilibrium

**Option C:** full equilibrium

**Option D:** unpredictable

**Correct Answer: **non-equilibrium ✔

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**Option A:** forces

**Option B:** independence of forces

**Option C:** dependence of forces

**Option D:** balance of force

**Correct Answer: **forces ✔

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**Option A:** kW (kilowatt)

**Option B:** hp (horse power)

**Option C:** kcal/sec

**Option D:** kg m/sec

**Correct Answer: **kcal/kg sec ✔

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**Option A:** Momentum and impulse

**Option B:** Torque and energy

**Option C:** Torque and work

**Option D:** Kinetic energy and potential energy

**Correct Answer: **Moment of a force and angular momentum ✔

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**Option A:** P/2 cos 9/2

**Option B:** IP sin 9/2

**Option C:** 2P tan 9/2

**Option D:** IP cos 9/2

**Correct Answer: **IP cos 9/2 ✔

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**Option A:** newton meter

**Option B:** watt

**Option C:** joule

**Option D:** kilogram meter/sec

**Correct Answer: **watt ✔

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